I guess you simply need to add
echo $shorturl;
at the end of your code in process.php.
shreedhan
Last Activity: Sep 18 '10, 10:06 AM
Joined: Jul 30 '07
Location: Kathmandu, Nepal
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Yes, of course I can ping the server. The problem is it isn't working even on same server. If I open http://172.31.72.77 on same server, it won't work. But http://localhost does work.
Thanks...Leave a comment:
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problem in hosting site over LAN
Hi,
I'm not sure whether this is the correct place to ask this question.
I have installed easyphp 3.0 and hosted on my local computer. I needed it to host over a LAN. With easyphp I can see the site using http://localhost or http://127.0.0.1 only. I'm not able to view the site from anywhere else.
My PC has an static IP 172.31.72.77. If I try to open this page http://172.31.72.77 in my own PC, then also it doesn't work. It says... -
Hi all,
I'm writing again here because I think I figured out the problem (not the solution). Sorry for not being completely descriptive previously.
I have two classes on same file . One of the methods in a class parses an XML file and returns String.
This string is used in another method of another class to load an image.
Now the code
...Code:class parse_Xml { private DocumentLeave a comment:
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I tried this one as well. But its giving the same result..
Thanks...Leave a comment:
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The code I'm using is following..
...Code:public BufferedImage loadimage(String name){ URL url=null; try{ System.out.println("name: "+name); url=getClass().getClassLoader().getResource(name); System.out.println(url); url=getClass().getClassLoader().getResource("shreedhan.gif"); System.out.println(url);Leave a comment:
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Thanks for your reply
I tried the above mentioned code and the output was
It shows "null" when "name" is there..Code:name: abc.jpg null file:/home/Shreedhan/workspace/test_4_sep/bin/abc.jpg
and it shows full path when "abc.jpg" is there..
I even tried concatenating the path to the name, but then it didn't work..
...Leave a comment:
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getClass().getClassLoader().getResource() problem....
Hi,
I'm very new to java... and I'm having a problem in getting a URL
This code works well when I supply a filename "abc.jpg" directly instead of name. But if I get the filename in "name" string.. then, the returned url value is null.Code:URL url; url=getClass().getClassLoader().getResource(name); System.out.println(url);
is there any difference in sending the argument... -
Thanks Garrow for the solution.
I am now convinced that I can't get outside of /var/www/html (except using symlinks).Leave a comment:
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Hey,
Thanks for clearing most of my doubts.
But stll I have a doubt.
I have created a directory /usr/tmp/uploads
/usr has read and execute permissions for all
tmp has read, write and execute permissions for owner, group and others all.
and I have given read, write, and execute permission to the uploads directory as well.
Even then it's not showing the image....Leave a comment:
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Thanks for replying. But, yeah, your question was somewhat stupid.
Let me explain my problem.
I'm using apache to host (locally) in my own PC (using fedora 6).
I have a html file which includes an image. (plz remember I'm fully aware that I should give complete path of the image and I have done that)
Now I can open this file in 2 ways.
1. Just double click this file to view it in some browser...Leave a comment:
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Problem in including any file in html while hosting
Hi all,
First of all, I use linux (fedora 6) and apache to host
I have a problem of including any file in html while hosting only
Even a simple code like
[HTML]<img src="/home/user/abc.jpg" />[/HTML]
won't show the included image.
To make it more clear,
If I view same page just opening it (not hosting) like
file:///home/user/abc.html
It shows... -
You can include this line
[HTML]
<head>
<bgsound src="sth.mid" loop=-1 />
</head>
[/HTML]
loop=-1 plays the sound forever. If you specify some number, the sound will be played that no. of times.
Hope it will help youLeave a comment:
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Have you included
session_start() ;
in another page or not?
You need to start a session in another page as well.Leave a comment:
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Hey,
I didn't use $_GET['name'] to retrieve the value.
Its working after I user $_GET array.
thanks for all your help and support.
I got that working now.
Thanks againLeave a comment:
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I think the problem is here
You need to start a session in every page, even if you are just accessing previous values from the _SESSION array.
So, initially a session will be started since $_SESSION is empty. But next time, $_SESSION array is set. So the code above doesn't start a session, if the array is set.
How about trying just
[PHP]session_start() ;[/PHP]
...Leave a comment:
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Hi,
thanks for your suggestions.
I have tried printing the value of $val[0] as well and it's working fine.
I can see in the page source as well as the url like pictures.php?na me=something but it seems name is not taking that value.
later when I include
[PHP]print ("\n<br/><center><img src=\" $name \"><br/>");[/PHP]
name doesn't have any value.
...Leave a comment:
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Well, I think I should explain my code.
I am trying to make a page for pictures in which user will see thumnail-size pictures first. And when he clicks the picture, he will see the actual size of image later on the same page.
Ok, now I have included this code in line no. 14
[PHP]#
printf("<a href=\"pictures .php?name=%s\"> ",urlencode($va l[0]));[/PHP]
Isn't this suppose...Leave a comment:
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OK,
here is the code I'm using
[PHP]<?php
$loginid=$_SESS ION['loginid'];
mysql_connect(' localhost','use r','user');
mysql_select_db ('test');
$query="select name from pictures where loginid='$login id'";
$result=mysql_q uery($query);
print("<table width=95% align=center cellspacing=4> <tr>");
$count=0;
while($val=mysq l_fetch_array($ result))
...Leave a comment:
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I have included following line
[PHP]print ("$name");[/PHP]
in pictures.php
just after above code.
thanks...Leave a comment:
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