Combine output in python after break

[Jane Janey]

I want to combine two of my print statement so that it has no gap in between. How do I remove gap after break? This is my code:

alpha1 = 'a'
    n = 6 
    while alpha1:
       n -= 1
       print "%-*s" % (10, alpha1*n) + "%*s" % (10, alpha1*n)
       if n < 0:
            break
    m = 0
    while alpha1:
       m += 1
       print "%-*s" % (10, alpha1*m) + "%*s" % (10, alpha1*m)
       if m > 4:
            break

The out put will be:

    aaaaa          aaaaa
    aaaa            aaaa
    aaa              aaa
    aa                aa
    a                  a

    a                  a
    aa                aa
    aaa              aaa
    aaaa            aaaa
    aaaaa          aaaaa

How do I remove the gap so that the output will be like this?

    aaaaa          aaaaa
    aaaa            aaaa
    aaa              aaa
    aa                aa
    a                  a
    aa                aa
    aaa              aaa
    aaaa            aaaa
    aaaaa          aaaaa

[bvdet]

You need only change two of the numbers.

alpha1 = 'a'
n = 6 
while True:
   n -= 1
   print "%-*s" % (10, alpha1*n) + "%*s" % (10, alpha1*n)
   if n < 2:
        break
m = 1
while True:
   m += 1
   print "%-*s" % (10, alpha1*m) + "%*s" % (10, alpha1*m)
   if m > 4:
        break

Output:

>>> aaaaa          aaaaa
aaaa            aaaa
aaa              aaa
aa                aa
a                  a
aa                aa
aaa              aaa
aaaa            aaaa
aaaaa          aaaaa
>>>

[bvdet]

Here's a version I like better:

letter = "a"
no_letters = 5
output = []
for i in range(no_letters, 1, -1):
    output.append("%-*s%*s" % (10, letter*i, 10, letter*i))
for i in range(1, no_letters+1):
    output.append("%-*s%*s" % (10, letter*i, 10, letter*i))
print "\n".join(output)