Code:
alpha1 = 'a'
n = 6
while alpha1:
n -= 1
print "%-*s" % (10, alpha1*n) + "%*s" % (10, alpha1*n)
if n < 0:
break
m = 0
while alpha1:
m += 1
print "%-*s"
Jane Janey
Last Activity: May 23 '13, 08:59 AM
Joined: Apr 18 '13
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Combine output in python after break
I want to combine two of my print statement so that it has no gap in between. How do I remove gap after break? This is my code:
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python symmetric words
I have to write a function which takes one arguments text containing a block of text in the form of a str, and returns a sorted list of “symmetric” words. A symmetric word is defined as a word where for all values i, the letter i positions from the start of the word and the letter i positions from the end of the word are equi-distant from the respective ends of the alphabet. For example, bevy is a symmetric... -
Python least characters function
I have to write a function which takes one argument text containing a block of text in the form of a str, and returns an alphabetically sorted list of word(s) with the lowest “vowel proportion” as a list. The vowel proportion is defined as the proportion of letters in the word which are vowels (e.g. the vowel proportion of "life" is 2 = 0.5). -
Python symmetric words
How do I write code to find words that are in the same specified position in a string. The position should be like this:
An example:Code:word1= ('a','b','c','d','e','f','g','h','i','j','k','l','m') word2= ('z','y','x','w','v','u','t','s','r','q','p','o','n') word1[n] == word2[n]
And it will return the result:Code:text = "A boy is being bully by Aloz"
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