How to get possible words from the given letters?

[Jimmy45]

Hello,

I am writing a "scrabble code" on Python. I have some problem with getting possible words from the given letters. For example:
Given letters are: 'c', 'r', 'n', '*'
Here '*' can be any letter.
Possible words: 'cry', 'corn', 'run', etc.
proper_word_lis t is a file containing all the english words.
score_of_word is a function that computes the score of the word.
hand is the letters that are given to the player

Following is my code (it gets only the possible words without star in hand):

def get_possible_words(hand, proper_word_list, score_of_a_letter_list) :
    
    possible_words = []
    for j in range(len(proper_word_list)):
        k = list(proper_word_list[j])
        k.sort()
        c = "".join(k)
        d = list(hand)
        d.sort()
        m = "".join(d)
        if c in m:
            l = (score_of_word(c, score_of_a_letter_list), proper_word_list[j])
            possible_words.append(l)
    possible_words.sort()
    possible_words.reverse()
    return possible_words

Thank you in advance.

[bvdet]

I take it this is homework? I would approach it this way:

1. Save the given letters ['c', 'r', 'n', '*'] - listA
2. Create another list, leaving out the asterisk ['c', 'r', 'n'] - listB
3. Open the file, creating a file object
4. Initialize a list to contain the matching words - output
5. Iterate on the file object, using variable line
6. Strip the newline character
7. If the length of the stripped line is in between the lengths of listA and listB
8. and if each letter in listB is in line, append to output

See if this helps. I think calculating the word score would be straightforward , but post again if you have any more questions.

[Jimmy45]

I take it this is homework? I would approach it this way:

1. Save the given letters ['c', 'r', 'n', '*'] - listA
2. Create another list, leaving out the asterisk ['c', 'r', 'n'] - listB
3. Open the file, creating a file object
4. Initialize a list to contain the matching words - output
5. Iterate on the file object, using variable line
6. Strip the newline character
7. If the length of the stripped line is in between the lengths of listA and listB
8. and if each letter in listB is in line, append to output

See if this helps. I think calculating the word score would be straightforward , but post again if you have any more questions.

Thank you for your kind attention to my question. Yes, I am doing my python homework. I have a question about how to check if every element in one list is contained in the another list. For example:
a = ['a', 'b', 'c'] and b = ['c', 'a']

[woooee]

Sets do that

a = set(['a', 'b', 'c'])
b = set(['c', 'a'])
print b.issubset(a)

[Jimmy45]

Sets do that

a = set(['a', 'b', 'c'])
b = set(['c', 'a'])
print b.issubset(a)

Is there any other way to do it? Because we can't use any set command in our homework.


Thank you.

[bvdet]

Maybe this will help:

>>> listA = ['a','b','c']
>>> word = 'abacus'
>>> [(c in word) for c in listA]
[True, True, True]
>>> None in [(c in word) for c in listA]
False
>>>

[Jimmy45]

Hello!

I am doing my homework and trying to get possible words from given letters.
For example:
Here is your hand: AONEP

Enter your word: ?
(POPPA, 11)
(NAPPE, 9)
(NAPPA, 9)
(POPE, 8)
(POOP, 8)
(PEPO, 8)
(PEEP, 8)
(PAPA, 8)

It must use p only once, but here is more that one. Can you please help me to find my mistake. Following is my code:

proper_word_lis t is given and it is converted to list in the another function.
hand is the letters given to the player.

 def get_possible_words(hand, proper_word_list, score_of_a_letter_list) :
    
    possible_words = []
    for j in range(len(proper_word_list)):
        if len(proper_word_list[j]) <= len(hand):
            str1 = ""
            for letter in proper_word_list[j] :
                if letter in hand:
                    str1 = str1 + letter 
                if '*' in hand:
                    num_of_l = len(str1)
                    num_of_ast = hand.count('*')
                    num_dif = len(proper_word_list[j]) - num_of_l
                    if num_of_ast >= num_dif:
                        str1 = proper_word_list[j]
                else:
                    str1
        if str1 == proper_word_list[j]:
            l = (score_of_word(str1, score_of_a_letter_list), str1)
            possible_words.append(l)
    possible_words.sort()
    possible_words.reverse()
    return possible_words

Thank you in advance.