Recognize a word from a list within a user input

[Netwatcher]

Hello, i am trying to make a program that recognizes a certain word from a list (as shown below),
My main problem is-
how do i make something that finds if the word from the given list is inside the user input, and by that i mean that the user input for 'hi' can be 'hi dude' and it doesn't has to be only 'hi'

import random
from time import sleep
hi='hi','HI','Hi','hI'
hello='hello','Hello','HELLO'
howdy='howdy','Howdy','HOWDY','HowDy'
while 1:
    X=raw_input(random.choice(anything))
    if hi in X :
        print "<!--I'm  A  Comment-->"
        print random.choice(hello)
        break
    elif X in hello:
        print "<!--I'm A different Comment-->"
        print random.choice(hi)
        break
    elif X in howdy:
        print '<!--I am something completely different-->'
    elif X in curses:
        print random.choice(anticurse)
    sleep(0.5)

This problem had bothered me for too long...
Thank you in advance

[bvdet]

It appears that you are comparing various combinations of upper and lower case letters of the same letters. Have you tried comparing the lower case word to the string in lower case?:[code=Python]>>> if 'hi' in 'ABCDEFGHiJKLM' .lower():
... print "It's in here."
...
It's in here.
>>> [/code]You could also do something like this:[code=Python]>>> hi = ('hi', 'HI', 'Hi', 'hI')
>>> for word in hi:
... if word in 'ABCDEFGHiJKLM' :
... print '%s is in phrase %s' % (word, 'ABCDEFGHiJKLM' )
...
Hi is in phrase ABCDEFGHiJKLM
>>> [/code]

[Netwatcher]

Finally,
Thank you!
I find the following code more useful for my purpose:

X=raw_input(random.choice(anything)).lower()

i tried this weird combination and luckily for me, it worked :D
solved me lots of problems and troubles

Thanks again!

[Netwatcher]

Awww... bummer...

i got another problem!

curses: 'eggs','bacon','spam'
def curse(X):
    for word in curses:
        if word in X:
            print random.choice(anticurse)
        else:
            print'<--ooʇ ʇuǝɯɯoɔ ɐ ɯ,ı--¡>'
        return(1)
  

while 1:
    X=raw_input(random.choice(anything)).lower()
    if hi in X:
        print "<!--I'm  A  Comment-->"
        print hello
        #break
    elif hello in X:
        print "<!--I'm A different Comment-->"
        print hi
        #break
    else:
        callable(curse(X))

When i run this code it only works for the first entry in the tuple (i tried with list and other groupings, but the problem remains)> if i enter 'eggs and ham'
it recgonize it but if i enter 'bacon and ham' or just 'bacon' or 'spam' it doesn't.

[boxfish]

That makes sense. Did you know that a return statement instantly exits the function? You're checking the first word, then you get to the bottom of the loop, and you return. I don't know what the return is for, but it's definitely in the wrong place.

[Netwatcher]

I do that, because, if i don't it prints '<--ooʇ ʇuǝɯɯoɔ ɐ ɯ,ı--¡>' 6 times in a row, with the return() it doesn't.
i have no idea why (it seems weird for me too),
but it works...

[boxfish]

It doesn't do that over and over because the loop is not looping. It only makes it through the first iteration. Without the return, your program prints '<--ooʇ ʇuǝɯɯoɔ ɐ ɯ,ı--¡>' whenever a particular curse is not in X. It should do that over and over unless X is particularly curse-filled. If you don't wan't to see '<--ooʇ ʇuǝɯɯoɔ ɐ ɯ,ı--¡>', then get rid of the print statement, but you can't have the return.

Hope this helps.

[Netwatcher]

Oh 'blip' hehe, i didn't notice that i can achieve the same effect that i wanted to get by doing
this-->

while 1:
    X=raw_input(random.choice(anything)).lower()
    if hi in X:
        print "<!--I'm  A  Comment-->"
        print hello
        #break
    elif hello in X:
        print "<!--I'm A different Comment-->"
        print hi
    else:
        for word in curses:
            if word in X:
                print random.choice(anticurse)
        if X not in curses:
            print '<--ooʇ ʇuǝɯɯoɔ ɐ ɯ,ı--¡>'

still prints it 6 times though...
it was my problem, sorry
is there a way to Not let the 'else' fill the missing curse?

[Netwatcher]

never mind i got it figured...