Error with fopen() function

[chazzy69]

So the function fopen() works most of the time heres the line im using-

 
$file = fopen($nextPage, "r") or exit("Unable to open file!");

But for some reason that i haven't been able to discern yet im getting "Unable to open file!" on specific urls this wouldn't be so much of a problem but it ends up hanging the rest of the program up.

Anyway so far i cant see any reason for the errors to occur becuase when theres a error i manually type in the url into a browser it works fine even though im getting a connection error.

So if anyone can help understand why there is an error occuring or better yet a way to skip a function if a error occurs.

Oh yer even if i continually repeat the the function i still get a connection error over and over again so i doesn't seem to be just a single random error.

Any helps with this problem is greatly appreciated,

Thanks in advance,

[dlite922]

So the function fopen() works most of the time heres the line im using-

 
$file = fopen($nextPage, "r") or exit("Unable to open file!");

But for some reason that i haven't been able to discern yet im getting "Unable to open file!" on specific urls this wouldn't be so much of a problem but it ends up hanging the rest of the program up.

Anyway so far i cant see any reason for the errors to occur becuase when theres a error i manually type in the url into a browser it works fine even though im getting a connection error.

So if anyone can help understand why there is an error occuring or better yet a way to skip a function if a error occurs.

Oh yer even if i continually repeat the the function i still get a connection error over and over again so i doesn't seem to be just a single random error.

Any helps with this problem is greatly appreciated,

Thanks in advance,

This is generally a basic function. There's not much code there to "help" you debug. All you need to do is check to make sure the $nextPage variable is going to a correct path. It wouldn't hurt to just echo that variable.

As far as the exiting when a function fails, this is PHP default fault exception behavior. PHP exits when a fatal error occurs, whether or not display_errors is on. You need to remove that "or exit(....)" part (because that exits the processes if the function returns false or errors) and then put a @ sign infront of the function to suppress that function (such as @fopen() )

Hope that helps,




Dan

[chazzy69]

Error with fopen() function

Thanks ill try that out

[chazzy69]

Error with fopen() function

Ok just have one question when you said put @ in front of the function call to suppress it is this supposed to be at run time (when it compiles) or before??

Also i don't suppose there is a goto command in php??

Thanks for the help

[pbmods]

Heya, Chazzy.

The '@' operator suppresses any errors that a PHP statement generates (PHP: Error Control Operators - Manual).

Generally, you will see this error if Apache does not have read permissions for the file you're trying to open.

[chazzy69]

Oh sweet thanks i get it now

[chazzy69]

I fixed the problem thanks for your help pplz