Calculating Number of days in php

[realin]

hi guys..

I have made a function which counts the numbers of days or hours or minutes from the current datetime to the give datetime.. but i am confused while displaying number of days along with number of hours.. rest all works fine(I Suppose).
here is the code :
[CODE=PHP]

function day_counter($da te,$msg){
$today=time();

$day_to_count=s trtotime($date) ;
if($day_to_coun t>$today){
$rem=$day_to_co unt-$today;
}

else {if($today>$day _to_count){
$rem=$today-$day_to_count;

}}

if($rem>=86400) {
$days=$rem/86400;

$days=round($da ys,2);
$dys=(int)$days ;
$h=(float)strst r($days,".");

$h=round($h*24) ;
if($h==24)
$dys+=1;
if($h<=0 OR $h==24)
return "<b>".$dys. "</b> Days ".$msg;
return "<b>".$dys. "</b> Days <b>".$h."</b> Hours ".$msg;
}
if($rem>=3600){
$hours=$rem/3600;
$hours=round($h ours,2);
$hrs=(int)$hour s;
$mn=(float)strs tr($hours,".");
$mn=ceil($mn*60 );
if($mn<=0)
return "<b>".$hrs. "</b> Hours ".$msg;
return "<b>".$hrs. "</b> Hours <b>".$mn."</b> Minutes ";
}

if($rem>=60){
$min=$rem/60;
$min=round($min ,2);
$mnm=(int)$min;
$sec=(float)str str($min,".");
$sec=ceil($sec* 60);
if($sec<=0)
return "<b>".$mnm. "</b> Minutes ".$msg;
return "<b>".$mnm. "</b> Minutes <b>".$sec." </b>Seconds";
}
if($rem>0 && $rem<60){
return "<b>".$rem. "</b> Seconds".$msg;
}
}[/CODE]

And i want to know, is this the right way to get the decimal part of a number ?

[pbmods]

Heya, realin.

[code=php]
$fpart = $val - (int) $val;
[/code]

[realin]

Heya, realin.

[code=php]
$fpart = $val - (int) $val;
[/code]

hi again !!

thanks for the reply.. but is the rest of code,allright ?? i mean it doesnt calculate the number of hours accurately in the first case.. that means along with the number of days..

[pbmods]

Heya, Realin.

[code=php]
$diff = abs(time() - strtotime($date ));

$days = (int) ($diff / 86400);
$day_remainder = $diff % 86400;

$hours = (int) ($day_remainder / 3600);
$hour_remainder = $day_remainder % 3600;
[/code]

And so on....

I did it the long way the first time, too ~_^

[realin]

Heya, Realin.

[code=php]
$diff = abs(time() - strtotime($date ));

$days = (int) ($diff / 86400);
$day_remainder = $diff % 86400;

$hours = (int) ($day_remainder / 3600);
$hour_remainder = $day_remainder % 3600;
[/code]

And so on....

I did it the long way the first time, too ~_^

woah thanks.. pretty similar results.. but the code is short.. :)
thanks a lot