$_POST question

[JimS]

In the first if statement am I properly checking for a post variable? Also, is the post variable's name the same as the input name?

if(isset($_POST('job_select')))
{
	$job_name=$_POST('job_select');
	
	$result=mysql_query("SELECT DISTINCT labor_code FROM oats_jobs_users_laborCode where user='$user_name' and job_name='$job_name' order by job_name;"); 

	if($result)
	{
		echo "<select name=\"laborcode\" onchange=\"timecard.submit()\" > <option default=\"default\" value=\"\">Choose One</option>"; 
		while($row=mysql_fetch_row($result))
		{ 
			echo "<option value=\"$row[0]\">$row[0]</option>";
		} 
			echo "</select>";
}

[ronverdonk]

isset is fine to check the existence of a $_POST variable. However, this variable could be blank. So you'll have to check its contents.

You can assign the $_POST variable to any PHP variable name you like.

Ronald :cool:

[JimS]

If the variable is set it cannot be blank (response from drop down box)

Is it a problem that I am calling it via a function?

[iam_clint]

this might not work take a close look

if(isset($_POST('job_select')))

check this

if(isset($_POST['job_select']))
$job_name=$_POST['job_select'];

[rkagrawal]

$_POST is a variable and not a function .
You should use $_POST[] rather than $_POST() .

The same goes with $_GET , $_FILES etc etc.


Rahul Agrawal
Developer
Web2003 Corporation
www.web2003corp .com