Re: Displaying Images form a Directory
"Jameson" <jameson_ray@co mcast.net> wrote:[color=blue]
> If we take a look at it...[/color]
<?php
$dir = '.';
$sAltText = "Picture";
foreach (glob("*.jpg") as $file) {
echo "file: $file<br />\n";
echo "<i>filenam e:</i> <b>$file</b>, <i>filetype:</i> <b>" .
filetype($file) . "</b><br />\n";
echo '<img src="' . $file . '" border="0" alt="$sAltText" /><br />' .
"\n";
}
?>
[color=blue]
> ...Let's say we set the directory to $dir = '/Users/jray/Pictures';
> (a path that I can browse to just fine from the command line).
> Where is the $dir variable used in the rest of the script?[/color]
I used the $dir in one of the scripts and forgot to take it out this
one, or perhaps left it on purpose (unknown reason). :-)
The single dot indicates the current directory, two dots indicate
the parent directory of the current directory.
$dir = "..";
You could also use it as the path to the folder you want to parse
and applie the file exstension inside of it...
$dir = "../*.jpg";
[color=blue]
> If a directory is specified in the glob() function, I believe it
> just defaults to the directory that the script is in.[/color]
That's exactly the way I see it. No difference. I find it much
better to use relative paths right at the moment, using
"../images/*.jpg"
to get to the folder in question, rather than absolute paths,
"/images/*.jpg"
The script would read...
<?php
$dir = '/images/*.jpg';
$sAltText = "Picture";
foreach (glob($dir) as $file) {
echo "file: $file<br />\n";
echo "<i>filenam e:</i> <b>$file</b>, <i>filetype:</i> <b>" .
filetype($file) . "</b><br />\n";
echo '<img src="' . $file . '" border="0" alt="$sAltText" /><br />' .
"\n";
}
?>
As long as the web-root is set up properly, the "absolute
path" works fine on a website... let your root path be
'/Users/jray/' and the php file resides in, '/php', the images
reside in, '/images/'. So a php file in the php folder could
reference image files by using '../images/img.jpg' or
'/images/img.jpg'.
If you employed Explorer on a Windows system, you could
change from the currently viewed folder to another folder
by typing in ..\WINDOWS, or "..\Program Files\", or
...\WINDOWS\sys tem32\ into the address bar. Someone
had a patent or some such on using the slash to denote paths.
Thus Microsoft patented the backslash concept (don't quote
me though as I can't identify the source read years ago and
maybe my mind plays tricks on me).
It works the same way on Unix systems but you change the
backslashes to forward slashes.
I imagine it works similar on a Mac, but I'll let someone
with Mac experience confirm it. Let me know.
[color=blue]
> Thanks again for sticking with this. Sometimes is is good
> to have an understanding of how a function works across
> different operating systems.[/color]
Yes, especially when it all jives together and works in the
same or similar manners.
Hope that helps.
Jim Carlock
Post replies to the newsgroup.
"Jameson" <jameson_ray@co mcast.net> wrote:[color=blue]
> If we take a look at it...[/color]
<?php
$dir = '.';
$sAltText = "Picture";
foreach (glob("*.jpg") as $file) {
echo "file: $file<br />\n";
echo "<i>filenam e:</i> <b>$file</b>, <i>filetype:</i> <b>" .
filetype($file) . "</b><br />\n";
echo '<img src="' . $file . '" border="0" alt="$sAltText" /><br />' .
"\n";
}
?>
[color=blue]
> ...Let's say we set the directory to $dir = '/Users/jray/Pictures';
> (a path that I can browse to just fine from the command line).
> Where is the $dir variable used in the rest of the script?[/color]
I used the $dir in one of the scripts and forgot to take it out this
one, or perhaps left it on purpose (unknown reason). :-)
The single dot indicates the current directory, two dots indicate
the parent directory of the current directory.
$dir = "..";
You could also use it as the path to the folder you want to parse
and applie the file exstension inside of it...
$dir = "../*.jpg";
[color=blue]
> If a directory is specified in the glob() function, I believe it
> just defaults to the directory that the script is in.[/color]
That's exactly the way I see it. No difference. I find it much
better to use relative paths right at the moment, using
"../images/*.jpg"
to get to the folder in question, rather than absolute paths,
"/images/*.jpg"
The script would read...
<?php
$dir = '/images/*.jpg';
$sAltText = "Picture";
foreach (glob($dir) as $file) {
echo "file: $file<br />\n";
echo "<i>filenam e:</i> <b>$file</b>, <i>filetype:</i> <b>" .
filetype($file) . "</b><br />\n";
echo '<img src="' . $file . '" border="0" alt="$sAltText" /><br />' .
"\n";
}
?>
As long as the web-root is set up properly, the "absolute
path" works fine on a website... let your root path be
'/Users/jray/' and the php file resides in, '/php', the images
reside in, '/images/'. So a php file in the php folder could
reference image files by using '../images/img.jpg' or
'/images/img.jpg'.
If you employed Explorer on a Windows system, you could
change from the currently viewed folder to another folder
by typing in ..\WINDOWS, or "..\Program Files\", or
...\WINDOWS\sys tem32\ into the address bar. Someone
had a patent or some such on using the slash to denote paths.
Thus Microsoft patented the backslash concept (don't quote
me though as I can't identify the source read years ago and
maybe my mind plays tricks on me).
It works the same way on Unix systems but you change the
backslashes to forward slashes.
I imagine it works similar on a Mac, but I'll let someone
with Mac experience confirm it. Let me know.
[color=blue]
> Thanks again for sticking with this. Sometimes is is good
> to have an understanding of how a function works across
> different operating systems.[/color]
Yes, especially when it all jives together and works in the
same or similar manners.
Hope that helps.
Jim Carlock
Post replies to the newsgroup.
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