Displaying Images form a Directory

[Jameson]

Happy New Year, Everyone!

I am trying to figure out how to display a bunch of images (mainly
JPEGs, but possibly a few GIFs and PNGs as well) that are stored in a
local directory on the system. I can do this with the glob() function,
but I can't seem to put in a directory other than one within the
webroot. For example, I can only put "/uploads" and not
"/Volumes/jray/Pictures...".

Any ideas how to get around this? If I can't use the glob function,
it's fine, but I only want images to be displayed (and not any other
file that happpens to be stored in that directory).

Thanks in advance!

[witkey]

Re: Displaying Images form a Directory

<?php
// An Example about listing Images.
$dir = ".";
$odir = opendir($dir);
while($file = readdir($odir)) {
if(filetype($fi le) == "image/JPEG") {
echo $file;
}
?>

[Jameson]

Re: Displaying Images form a Directory

Thanks for the fast response. What I'm trying to do is actually display
the images, not list them. What I've got so far (sorry for not posting
this earlier) is:

<?php
echo "<table><tr >";

foreach(glob("u ploads/*.{jpg,JPG,jpeg ,JPEG,gif,GIF,p ng,PNG}",
GLOB_BRACE) as $images)
{
echo "<td><img src=\"".$images ."\"><br/>";
}

echo "</tr></table>";
?>

It works just fine if I want to view images in the "uploads/" folder
(which is parallel to this script), but if I want to change it to be
"/Volumes/jray/Pictures" it won't work.

witkey wrote:[color=blue]
> <?php
> // An Example about listing Images.
> $dir = ".";
> $odir = opendir($dir);
> while($file = readdir($odir)) {
> if(filetype($fi le) == "image/JPEG") {
> echo $file;
> }
> ?>[/color]

[Chung Leong]

Re: Displaying Images form a Directory

Well, if the images aren't within the webroot, then the web server
won't serve them...

[Jim Carlock]

Re: Displaying Images form a Directory

"Jameson" <jameson_ray@co mcast.net> wrote:[color=blue]
> Thanks for the fast response. What I'm trying to do is
> actually display the images, not list them. What I've
> got so far (sorry for not posting this earlier) is:[/color]

Use witkey's suggestion with a modification?

<?php
// An Example about listing Images.
$dir = ".";
$odir = opendir($dir);
while($file = readdir($odir)) {
if(filetype($fi le) == "image/JPEG") {
$sAltText = '"Whatever the alt text is if so required."';
echo '<img src="' . $dir . $file . ' border="0" alt="' . $sAltText . '" /><br />' . "\n";
}
?>

Jim Carlock
Post replies to the newsgroup.

[Jerry Stuckle]

Re: Displaying Images form a Directory

Chung Leong wrote:[color=blue]
> Well, if the images aren't within the webroot, then the web server
> won't serve them...
>[/color]

Not true. You can serve them through PHP, e.g.

<img src="showimg.ph p"...>

And showimg.php can be something like:

header('Content-type: image/gif');
header('Content-length: '.filesize($img _filename));
$file_pointer = fopen('/some/other/directory/img.gif', 'rb');
fpassthru($file _pointer);
fclose($file_po inter);

The graphic can reside anywhere on the system which is accessible to the
Apache process (not just under DocumentRoot).

--
=============== ===
Remove the "x" from my email address
Jerry Stuckle
JDS Computer Training Corp.
jstucklex@attgl obal.net
=============== ===

[Jameson]

Re: Displaying Images form a Directory

Hi Jim:

Thanks for the suggestion. I tried it out, but still got a blank
screen. I think Chung might be right, because if I try "<img
src="/Library/WebServer/Documents/uploads/door.jpg>" the web server
won't serve them. I think the client's browser is trying to find the
images locally on the HD.

Maybe what I'm trying to do isn't possible. Do you think using the
glob() function within the opendir() function might work?

Thanks for all of the help!

Jim Carlock wrote:[color=blue]
> "Jameson" <jameson_ray@co mcast.net> wrote:[color=green]
> > Thanks for the fast response. What I'm trying to do is
> > actually display the images, not list them. What I've
> > got so far (sorry for not posting this earlier) is:[/color]
>
> Use witkey's suggestion with a modification?
>
> <?php
> // An Example about listing Images.
> $dir = ".";
> $odir = opendir($dir);
> while($file = readdir($odir)) {
> if(filetype($fi le) == "image/JPEG") {
> $sAltText = '"Whatever the alt text is if so required."';
> echo '<img src="' . $dir . $file . ' border="0" alt="' . $sAltText . '" /><br />' . "\n";
> }
> ?>
>
> Jim Carlock
> Post replies to the newsgroup.[/color]

[Jim Carlock]

Re: Displaying Images form a Directory

Hi Jameson,

<g> I feel like I'm talking to a son... (j.k)

I didn't test the witkey's code. It appears that filetype()
returns "file" or "dir". Try the following.

<?php
// An Example about listing Images.
$dir = ".";
$dh = opendir($dir);
// skip the . and ..
$file = readdir($dh);
$sAltText = 'Picture';
// skip . and ..
if ($file == ".") {
$file = readdir($dh); $file = readdir($dh);
do {
if (mime_content_t ype($file)=="im age/jpeg") {
echo '<img src="' . $dir . $file . '" border="0" alt="' . $sAltText . '" /><br />' . "\n";
} while($file = readdir($dh));
}
}
closedir($dh);
?>

That should work I think. It's air code. I tested it out here
but I'm running into a problem where the mime_content_ty pe
is a problematic function right at the moment.

I read that the glob function is supposed to be a better
alternative in the PHP manual. And if you know that
all the files in the folder are jpg's then you won't have to
do the mime_content_ty pe test.

My apologies about not testing witkey's code. Hope this helps.

If anyone knows how to get the php_mime_magic. dll
file to work on a Windows system, I could use the help.
I uncommented the line in php.ini...

extension=php_m ime_magic.dll

and put the php_mime_magic. dll in the system32 folder.
Then I stopped apache and restarted apache...

net stop apache
net start apache

Thanks, much.

Jim Carlock
Post replies to the newsgroup.

[Jameson]

Re: Displaying Images form a Directory

Hi Jim:

Thanks for the new code. I think we're getting closer, but it still
doesn't seem to be working. I added the error reporting code below to
the file, but it doesn't tell me that anything is wrong. It's strange,
because I don't even see an icon from the browser saying that it can't
find the image. Do you think I could be missing some component of my
PHP installation? I know the directory path is fine, because I can get
to it right from the terminal on the computer.

ini_set("displa y_errors",true) ;
error_reporting (E_ALL );

Any more ideas? Do you think if I used the glob() function within the
opendir() function, it might work?

Thanks again for the help. I really appreciate it!

[Jim Carlock]

Re: Displaying Images form a Directory

"Jameson" <jameson_ray@co mcast.net> wrote:[color=blue]
> Thanks for the new code. I think we're getting closer, but it still
> doesn't seem to be working.[/color]

Hi Ray,

Are you working in the MacIntosh environment? I'm working on
with a PC. On the PC, the php.ini file typically gets found in the
system32 folder. I'm not sure how things work on a MacIntosh,
so perhaps you can explain the php.ini concepts relating to
MacIntosh (if that is the case) for my benefit. The php stuff is
very new to me.

I did get the following code to work here, using glob(). I really
like this better than having to do mime_content_ty pe stuff. And
so much in the PC and unix world seem very much related,
using file extensions to denote the contents of the file.

<html>
<head>
<title>List of Files</title>
</head>
<body>
<p><?php
$dir = '.';
$sAltText = "Picture";
foreach (glob("*.jpg") as $file) {
echo "file: $file<br />\n";
echo "<i>filenam e:</i> <b>$file</b>, <i>filetype:</i> <b>" . filetype($file) . "</b><br />\n";
echo '<img src="' . $file . '" border="0" alt="$sAltText" /><br />' . "\n";
}
?></p>
</body></html>
[color=blue]
> I added the error reporting code below to the file, but it doesn't
> tell me that anything is wrong. It's strange, because I don't even
> see an icon from the browser saying that it can't find the image.[/color]

When you view the page through the browser, take a look at the
source code (the HTML output). The code I posted previously
seems to have had a small bug in one of the lines, and I gave up
testing it when I couldn't get the php_mime_magic. dll to provide
the php_mime_conten t() function. So I don't know how the
Mac environment works, nor the Unix environment. The file name
could possibly be of a different extension in each environment. If
anyone else here can provide a little help here that would be
great.
[color=blue]
> Do you think I could be missing some component of my PHP
> installation? I know the directory path is fine, because I can get
> to it right from the terminal on the computer.[/color]

ini_set("displa y_errors",true) ;
error_reporting (E_ALL );
[color=blue]
> Any more ideas? Do you think if I used the glob() function within
> the opendir() function, it might work?[/color]

glob() is alot easier... there's no need for opendir() and readdir()
when using the glob function.

I just tested the following out and it works quite well.

<?php
$dir = '.';
$sAltText = "Picture";
foreach (glob("*.jpg") as $file) {
echo "file: $file<br />\n";
echo "<i>filenam e:</i> <b>$file</b>, <i>filetype:</i> <b>" . filetype($file) . "</b><br />\n";
echo '<img src="' . $file . '" border="0" alt="$sAltText" /><br />' . "\n";
}
?>
[color=blue]
> Thanks again for the help. I really appreciate it![/color]

You're welcome. I'm learning as well. So thanks back at you!

My mime_content_ty pe() function is failing I think, because
the directory path for the php install folder is set to C:\php4
and php isn't installed there. So I guess I need to find the
source code for that particular DLL and modify the source
code. If anyone knows where to pick up the source code
for the php_mime_magic. dll feel free to leave a hint. It's a
shame (for me and others) that the people that compiled it
used an absolute path inside the DLL file.

Jim Carlock
Post replies to the newsgroup.

[Jim Carlock]

Re: Displaying Images form a Directory

Hello again,

I finally got the mime_magic stuff to work. I ended up
editing php.ini to get it to work.

The following line was commented out so all I did was
uncomment it.

extension=php_m ime_magic.dll

Also, I had to add a section with the following item:

[mime_magic]
mime_magic.magi cfile = "C:\path\to\PHP \install\extras \magic.mime"

The following code works very well, but I still like the glob()
function more.

// view the mime type
$rpn = "23939.jpg" ;
echo mime_content_ty pe($rpn);

returns "image/jpeg". Also, if the file is named 23939 without
the .jpg extension, mime_content_ty pe('23939'); also returns
"image/jpeg". I tested dropping the extension on a .gif file as
well and it correctly returned, "image/gif".

Hope this helps.

Jim Carlock
Post replies to the newsgroup.

[feo]

Re: Displaying Images form a Directory

header ( 'Content-Type: ' . image_type_to_m ime_type ( $img ) );
readfile ( $img );

$img is the relative path to the image file. Let's say you use this tree:

/directory_for_e verything
/directory_for_e verything/directoryforsto ringimages
/directory_for_e verything/directoryhttpex posed

If your script is stored in the last directory, then $img =
'../directoryforsto ringimages/nameofimage';

Hope it helps.

feo

"Jameson" <jameson_ray@co mcast.net> escribió en el mensaje
news:1136134747 .652428.106160@ g44g2000cwa.goo glegroups.com.. .[color=blue]
> Happy New Year, Everyone!
>
> I am trying to figure out how to display a bunch of images (mainly
> JPEGs, but possibly a few GIFs and PNGs as well) that are stored in a
> local directory on the system. I can do this with the glob() function,
> but I can't seem to put in a directory other than one within the
> webroot. For example, I can only put "/uploads" and not
> "/Volumes/jray/Pictures...".
>
> Any ideas how to get around this? If I can't use the glob function,
> it's fine, but I only want images to be displayed (and not any other
> file that happpens to be stored in that directory).
>
> Thanks in advance!
>[/color]

[Jameson]

Re: Displaying Images form a Directory

Hi Jim:

Thanks a million for all of the help. I think my PHP installation isn't
set up right, because it seems like anything that I try do do with
images doesn't work very well.

I might try making a symbolic link (like a shortcut on Windows) in the
directory. I know it isn't as ideal as if I could get the directory
parth to wrok with the glob() function, but it might be all I've got at
this point.

I'm glad you got your mime_content_ty pe to work. Sometimes we get lucky
and it turns out to be as simple as uncommenting a line.

Thanks again for all of the help!

Jameson

Jim Carlock wrote:[color=blue]
> Hello again,
>
> I finally got the mime_magic stuff to work. I ended up
> editing php.ini to get it to work.
>
> The following line was commented out so all I did was
> uncomment it.
>
> extension=php_m ime_magic.dll
>
> Also, I had to add a section with the following item:
>
> [mime_magic]
> mime_magic.magi cfile = "C:\path\to\PHP \install\extras \magic.mime"
>
> The following code works very well, but I still like the glob()
> function more.
>
> // view the mime type
> $rpn = "23939.jpg" ;
> echo mime_content_ty pe($rpn);
>
> returns "image/jpeg". Also, if the file is named 23939 without
> the .jpg extension, mime_content_ty pe('23939'); also returns
> "image/jpeg". I tested dropping the extension on a .gif file as
> well and it correctly returned, "image/gif".
>
> Hope this helps.
>
> Jim Carlock
> Post replies to the newsgroup.[/color]

[Jim Carlock]

Re: Displaying Images form a Directory

"Jameson" <jameson_ray@co mcast.net> wrote:[color=blue]
> Thanks a million for all of the help. I think my PHP installation
> isn't set up right, because it seems like anything that I try do
> do with images doesn't work very well.[/color]

Hi Ray,

If you're as curious about how things work on a Windows NT
system as I am about how they work on a Mac, perhaps we
could continue and see if we come up with something.

For instance, are you doing all this on a MacIntosh system? I
see your posting to the newsgroup using a MacIntosh. That's
where my questions must start.

X-HTTP-UserAgent:
Mozilla/5.0 (Macintosh; U; PPC Mac OS X; en)
AppleWebKit/416.12 (KHTML, like Gecko) Safari/416.13,gzip(gfe ),gzip(gfe)

Apache gets installed as a "Service" on any NT system. How do
you start and stop a web-server on the Mac?

Here we either click on Start, Run then type in services.msc, or
we open a command prompt and type services.msc, or we open
a command prompt and use the following commands to start and
stop the service...

net stop Apache
net start Apache

The services.msc provides the GUI interface and opens a window
whereby you can right click on each listed service, then select "Stop"
or "Start" or get into the service "Properties " to set the Autostart
stuff.

The PHP stuff loads when Apache starts. That's the only way
it gets loaded. The executable, php.exe, isn't even in the PATH
environment variable. So the PHP install folder holds some files
but everything to load gets identified in the PHP.INI file. I forgot
to mention something about the "extension_ dir" line found in
PHP.INI:

extension_dir = "C:/WINDOWS/system32/"

This line positively identifies the location of the folder which
holds the extension files. Shortcuts to .dll files do not work on
a Windows system, so the actual .dll must reside in the folder
specified. Also, the path must be specified using the forward
slash, even though Windows itself uses backwards-slashes to
denote a path to a file.

So I ended up using the "net stop Apache" and "net start Apache"
to test things. The "net start ..." and "net stop ..." commands are
extremily useful on any Windows NT system (NT, 2000, XP,
2003).

So my next question is, do you employ a PHP.INI file on a Mac?

You are trying to get this to work on a Mac, right? If you're
unsure of how to answer any of the questions, let me know.
I'm really ignorant when it comes to MacIntosh systems, and
I might be able to ask some easy to answer questions if your
willing to answer some questions. I'm certainly eager to get
answers and explore this, even though no Mac sits in front of
me. :-)

Jim Carlock
Post replies to the newsgroup.

[Jameson]

Re: Displaying Images form a Directory

Hi Jim:

Sure, I'd be happy to keep looking into this. Maybe we'll end up
getting it to work.

First off, I am doing this on a Mac. Apache comes built in to OS X (I
believe as a service), and I installed PHP from an install package.

There is a PHP ini file on the Mac, although I've never had to edit it.
I used to run a Windows 2000 server with PHP on it, and I had to edit
the PHP.ini file quite a few times.

Restarting Apache on the Mac can either be done through the command
line or System Preferences. I tend to do it from the GUI, but I think
that "apachectl restart" will restart it from the command line.

There was actually something that I was wondering about your last
version of the script. If we take a look at it...

<?php
$dir = '.';
$sAltText = "Picture";
foreach (glob("*.jpg") as $file) {
echo "file: $file<br />\n";
echo "<i>filenam e:</i> <b>$file</b>, <i>filetype:</i> <b>" .
filetype($file) . "</b><br />\n";
echo '<img src="' . $file . '" border="0" alt="$sAltText" /><br />' .
"\n";

}

?>

....Let's say we set the directory to $dir = '/Users/jray/Pictures'; (a
path that I can browse to just fine from the command line). Where is
the $dir variable used in the rest of the script? If a directory is
specified in the glob() function, I believe it just defaults to the
directory that the script is in. Did you have a different experience on
your end?

Thanks again for sticking with this. Sometimes is is good to have an
understanding of how a function works across different operating
systems.

Jameson