Problem in setting DateTime value explicitly.

[priyamtheone]

I want to pick a value from a DateTimePicker in 'MM/dd/yyyy hh:mm tt' format, add 00 as second with it, store it in a DateTime variable and save it to database. Suppose if I pick the value 05/28/2010 9:25 AM or 05/28/2010 9:25:34 AM from the DateTimePicker, it'll be stored in the variable and saved to database as 05/28/2010 9:25:00 AM irrespective of what value is chosen from the DateTimePicker for second. I'm using the following statement but it's getting failed during the format conversion while storing it in the DateTime variable generating an error.

Dim dtmReminderTime As DateTime
dtmReminderTime = DateTime.Parse( Format(dtpRemin derTime.Value, "MM/dd/yyyy hh:mm") + ":00 " + Format(dtpRemin derTime.Value, "tt"))

I tried the other way but failed:
dtmReminderTime = Convert.ToDateT ime(Format(dtpR eminderTime.Val ue, "MM/dd/yyyy hh:mm") + ":00 " + Format(dtpRemin derTime.Value, "tt"))

I have also tried using culture specific information but of no avail. Please help.

[tlhintoq]

Don't try parsing it... That's just a mess. Keep it as a DateTime object.
Get the DateTime.second s property. Then add a negative number of seconds to it. That will be :00

Suedocode - you'll have to make the VB version of this.

myDateTimeVaria ble = 05/may/2010 at 14:50:23
myDateTimeVaria ble.AddSeconds(-1 * myDateTimeVaria ble.Seconds);

[Plater]

Be sure to note that AddSeconds() (and similar functions) don't modify the active datetime object, but rather return a new one with the changes applied to it

[priyamtheone]

Don't try parsing it... That's just a mess. Keep it as a DateTime object.
Get the DateTime.second s property. Then add a negative number of seconds to it. That will be :00

Suedocode - you'll have to make the VB version of this.

myDateTimeVaria ble = 05/may/2010 at 14:50:23
myDateTimeVaria ble.AddSeconds(-1 * myDateTimeVaria ble.Seconds);

Optimum solution. Thanks.

[Curtis Rutland]

Be sure to note that AddSeconds() (and similar functions) don't modify the active datetime object, but rather return a new one with the changes applied to it

Very very true. I've spent hours chasing my tail not realizing why my code isn't working, only to later realize I was calling a method that returns its result rather than applying the result to the object that called it.

For the sake of completeness and to help anyone that comes across this post later, here is a corrected version of tlhintoq's example:

myDateTimeVariable = 05/may/2010 at 14:50:23
myDateTimeVariable = myDateTimeVariable.AddSeconds(-1 * myDateTimeVariable.Seconds);