javascript refresh a select box without refreshing page

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  • cleary1981
    New Member
    • Jun 2008
    • 178

    javascript refresh a select box without refreshing page

    Hi, I am trying to improve the usabilty of an app I have written and it would be great if I could refresh the content of my select boxes without refreshing the whole page.

    I am sure this could be done. perhaps using iFrames. Can anyone shed some light?
  • RamananKalirajan
    Contributor
    • Mar 2008
    • 608

    #2
    Refreshing the Select Box withut refreshing the page means in what way you want to refresh the select box. Wether are u adding the Database values into that select box or user defined values in that page should be added to the select box.

    Regards
    Ramanan Kalirajan

    Comment

    • cleary1981
      New Member
      • Jun 2008
      • 178

      #3
      the select box is populated from my database. when I add a new item to my database i want to see the values in the select box without refreshing.

      Comment

      • gits
        Recognized Expert Moderator Expert
        • May 2007
        • 5388

        #4
        so you want to push an update to a webapp when your database changes without user interaction? you just need to use an ajax-call and poll the db with it ... you have to decide how often you need that and you may use setInterval() for this purpose ... you just cannot really push things to the client ... the client has to request the update ...

        kind regards

        Comment

        • cleary1981
          New Member
          • Jun 2008
          • 178

          #5
          Yeah i have the function of adding to my database on the same page so when I add a new item to my database I want the selectbox which is a list of records to now contain the new one. Can you show me how this is done with ajax?

          Comment

          • gits
            Recognized Expert Moderator Expert
            • May 2007
            • 5388

            #6
            that is not nessecary then ... you could add the option to the DB with the call and besides that you just need to add it to the node with dom-methods to avoid requests/traffic ... what have you done so far?

            Comment

            • cleary1981
              New Member
              • Jun 2008
              • 178

              #7
              Its is neccessary because I have three select boxes linked together. I need to turn my requests into ajax requests. Thanks for your help anyway. Below are the unctions I am currently using to populate my select boxes

              Code:
              <?php
              
              require "config.php"; // database connection details 
              echo "
              
              function fillType(){
              	//this function is used to fill the companies in main.php on load
              ";	
              
              $q11=mysql_query("SELECT type FROM module_type");
              echo mysql_error();
              while($nt11=mysql_fetch_array($q11)){
              echo "addOption(document.form1.newtype, '$nt11[type]', '$nt11[type]');";}// end of while
              ?>
              }
              
              function fillType2() {
              
              removeAllOptions(document.form1.selecttype);
              addOption(document.form1.selecttype, "", "Select", "");
              <?php	
              $q77=mysql_query("SELECT type FROM module_type");
              echo mysql_error();
              while($nt77=mysql_fetch_array($q77)){
              echo "addOption(document.form1.selecttype, '$nt77[type]', '$nt77[type]');";}// end of while
              ?>
              }
              
              function fillNewSub() {
              	removeAllOptions(document.form1.newsub);
              	addOption(document.form1.newsub, "", "Select", "");
              
              	<?php
              		$q22=mysql_query("select distinct(type) from subtype"); 
              		while($nt22=mysql_fetch_array($q22)){
              			echo "if(document.form1.newtype.value == '$nt22[type]'){";
              			$q32=mysql_query("select subtype from subtype where type='$nt22[type]' order by subtype asc");
              			while($nt32=mysql_fetch_array($q32)){
              			echo "addOption(document.form1.newsub,'$nt32[subtype]', '$nt32[subtype]');";
              
              			} // end of while loop
              			echo "}"; // end of JS if condition
              		}
              ?>
              }
              
              function fillselectsub(){
              	removeAllOptions(document.form1.selectsub);
              	addOption(document.form1.selectsub, "", "Select", "");
              
              	<?php
              		$q55=mysql_query("select distinct(type) from subtype"); 
              		while($nt55=mysql_fetch_array($q55)){
              			echo "if(document.form1.selecttype.value == '$nt55[type]'){";
              			$q56=mysql_query("select subtype from subtype where type='$nt55[type]' order by subtype asc");
              			while($nt56=mysql_fetch_array($q56)){
              			echo "addOption(document.form1.selectsub,'$nt56[subtype]', '$nt56[subtype]');";
              
              			} // end of while loop
              			echo "}"; // end of JS if condition
              		}
              ?>
              }
              
              function fillselectmod(){
              	removeAllOptions(document.form1.selectmod);
              	addOption(document.form1.selectmod, "", "Select", "");
              
              	<?php
              		$q44=mysql_query("select distinct(subtype) from module"); 
              		while($nt44=mysql_fetch_array($q44)){
              			echo "if(document.form1.selectsub.value == '$nt44[subtype]'){";
              			$q45=mysql_query("select module_name from module where subtype='$nt44[subtype]' order by module_name asc");
              			while($nt45=mysql_fetch_array($q45)){
              			echo "addOption(document.form1.selectmod,'$nt45[module_name]', '$nt45[module_name]');";
              
              			} // end of while loop
              			echo "}"; // end of JS if condition
              		}
              ?>
              }
              
              
              function removeAllOptions(selectbox)
              {
              	var i;
              	for(i=selectbox.options.length-1;i>=0;i--)
              	{
              		//selectbox.options.remove(i);
              		selectbox.remove(i);
              	}
              }
              
              function addOption(selectbox, value, text )
              {
              	var optn = document.createElement("OPTION");
              	optn.text = text;
              	optn.value = value;
              
              	selectbox.options.add(optn);
              }

              Comment

              • gits
                Recognized Expert Moderator Expert
                • May 2007
                • 5388

                #8
                so you mean you have to update all three select-nodes when adding a new option to one of them? as i said ... then you need something that does the following steps:

                1. user adds an option
                2. start your ajax-call and insert the option to the db
                3. when inserted retrieve the data from the db
                4. send back the result
                5. the onreadystatecha nge-handler could now update the list-nodes

                Comment

                • cleary1981
                  New Member
                  • Jun 2008
                  • 178

                  #9
                  ok heres what I have for the first select. I can get the values into my program but how do I put the values into the select?

                  Code:
                  function ajax_filltype(){
                  	var x=0;
                  	var url = "filltype.php?x=" + escape(x);
                  	url = url + "&dummy=" + new Date().getTime();
                  	request.open("GET", url, true);
                  	request.onreadystatechange = populateselecttype;
                  	request.send(null); 
                  }
                  function populateselecttype() {
                  	if (request.readyState == 4) {
                  		var response = request.responseText;
                  		var splitResult = response.split("%%");
                  		for (i=0; i<splitResult.length-1; i++){
                  			alert(splitResult[i]);
                  			//add each option i to select box
                  		}
                  	}
                  	
                  }
                  php
                  Code:
                  <?php
                  
                  require "config.php";
                  
                  $q1=mysql_query("SELECT type FROM module_type");
                  while($r = mysql_fetch_array($q1)){
                  		echo $r['type'] . '%%';
                  	
                    }
                  ?>

                  Comment

                  • cleary1981
                    New Member
                    • Jun 2008
                    • 178

                    #10
                    never mind it was just

                    Code:
                    function populateselecttype() {
                    	if (request.readyState == 4) {
                    		var response = request.responseText;
                    		var splitResult = response.split("%%");
                    		for (i=0; i<splitResult.length-1; i++){
                    			document.form1.selecttype.options[document.form1.selecttype.length] = new Option(splitResult[i], splitResult[i]);
                    		}
                    	}
                    	
                    }

                    Comment

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