Delete duplicates array (String)

[Mokita]

Hello,


I am working with Taverna to build a workflow. Taverna has a beanshell where I can program in java. I am having some problems in writing a script, where I want to eliminate the duplicates in an array (String).


for (int k=0; k<myLength; k++){
boolean isthere=false;
for (int l=0; l<sizeres; l++){
if (res[l].equals(my[k])){
isthere=true;
break;
}
}
if (isthere == false){
res[free]= my[k];
temp.append(res[free] + "\n");
free++;
}
}

The beanshell gives me an error in the method .equals(my[k]).

Has anyone work with beanshell already?
Does anyone has an idea how to delete duplicates from an array of String in a easier way?

I also thought about java.util.Set, but it not working too.

Thank you in advance,

Mokita

[JosAH]

Hello,


I am working with Taverna to build a workflow. Taverna has a beanshell where I can program in java. I am having some problems in writing a script, where I want to eliminate the duplicates in an array (String).


for (int k=0; k<myLength; k++){
boolean isthere=false;
for (int l=0; l<sizeres; l++){
if (res[l].equals(my[k])){
isthere=true;
break;
}
}
if (isthere == false){
res[free]= my[k];
temp.append(res[free] + "\n");
free++;
}
}

The beanshell gives me an error in the method .equals(my[k]).

Has anyone work with beanshell already?
Does anyone has an idea how to delete duplicates from an array of String in a easier way?

I also thought about java.util.Set, but it not working too.

Thank you in advance,

Mokita

BeanShell is great fun to work/play with; as far as I know you can't use generics
yet so you have to do this (for arrays of Objects of any kind)

[code=java]
Set set= new HashSet(Arrays. asList(yourArra y));
[/code]

The set contains all your elements from yourArray but only once.

kind regards,

Jos

[Mokita]

BeanShell is great fun to work/play with; as far as I know you can't use generics
yet so you have to do this (for arrays of Objects of any kind)

[code=java]
Set set= new HashSet(Arrays. asList(yourArra y));
[/code]

The set contains all your elements from yourArray but only once.

kind regards,

Jos

Thank you very much, it was very helpful.

Mokita

[sriharis]

Reply...for removing duplicates in a array without collections in java

Hello,


I am working with Taverna to build a workflow. Taverna has a beanshell where I can program in java. I am having some problems in writing a script, where I want to eliminate the duplicates in an array (String).


for (int k=0; k<myLength; k++){
boolean isthere=false;
for (int l=0; l<sizeres; l++){
if (res[l].equals(my[k])){
isthere=true;
break;
}
}
if (isthere == false){
res[free]= my[k];
temp.append(res[free] + "\n");
free++;
}
}

The beanshell gives me an error in the method .equals(my[k]).

Has anyone work with beanshell already?
Does anyone has an idea how to delete duplicates from an array of String in a easier way?

I also thought about java.util.Set, but it not working too.

Thank you in advance,

Mokita

Reply:-

HI,
Try the following logic for String array.......... .

private static void removeDuplicate sFromArray(){
int exampleArray [] = {4,5,1,1,2,3,2, 4,5,1,2,0};// Example Array!
int exampleArrayLen gth = exampleArray.le ngth;
int searchArray [] = new int[exampleArrayLen gth]; // Empty Array used to remove duplicates from Example Array
int searchArrayLeng th=1;

//I now want to print the above array without any duplicate values, which is my problem!
for(int x = 0; x < exampleArrayLen gth; x++){
if(x==0){
searchArray[0] = exampleArray[0];
}else{
int elementFound=0;
for(int y=0;y<searchArr ayLength;y++){
if(exampleArray[x] != searchArray[y]){
elementFound=0;
}else{
elementFound=el ementFound+1;
break;
}
}
if(elementFound ==0){
searchArray[searchArrayLeng th] = exampleArray[x];
searchArrayLeng th++;
}
}
}

int outArray[]=new int[searchArrayLeng th];
System.arraycop y(searchArray,0 ,outArray,0,sea rchArrayLength) ;

for(int x = 0; x < outArray.length ; x++){
System.out.prin tln(outArray[x]);
}
}

Regards,
Karthik.

[JosAH]

Reply:-

HI,
Try the following logic for String array.......... .

Did you read reply #2? (eight months ago).

kind regards,

Jos