Regular expression question!

[pro]

Hi everyone,
I would like to ask something about regular expressions in java.

I have made a code lika that

cleanString = cleanString.replaceAll(";", " ; ");
cleanString = cleanString.replaceAll(":", " : ");
cleanString = cleanString.replaceAll(",", " , ");
cleanString = cleanString.replaceAll("`", " ` ");
cleanString = cleanString.replaceAll("!", " ! ");

Can I do it this with only one regular expression, because it seems very bad code.

I know that the first parameter could be
replaceAll("[;:,`!]", ) but the second parameter?



I would like the same for the expression

cleanString = cleanString.replaceAll("That's", " That is ");
cleanString = cleanString.replaceAll("that's", " that is ");

Thanks a lot

[JosAH]

Hi everyone,
I would like to ask something about regular expressions in java.

I have made a code lika that

cleanString = cleanString.replaceAll(";", " ; ");
cleanString = cleanString.replaceAll(":", " : ");
cleanString = cleanString.replaceAll(",", " , ");
cleanString = cleanString.replaceAll("`", " ` ");
cleanString = cleanString.replaceAll("!", " ! ");

Can I do it this with only one regular expression, because it seems very bad code.

I know that the first parameter could be
replaceAll("[;:,`!]", ) but the second parameter?



I would like the same for the expression

cleanString = cleanString.replaceAll("That's", " That is ");
cleanString = cleanString.replaceAll("that's", " that is ");

Thanks a lot

Read all about it in the Matcher class; for your example it would look like this:

[code=java]
cleanString= cleanString.rep laceAll("[;:,`!]", " $0 ");
[/code]
Note the spaces around the $0. The $ group designator refer to parts of the
previous regular expression or to the entire thing (denoted by $0).

kind regards,

Jos

[pro]

Thank you very much!

I would like also to ask what about brackets

How can I reaplace with something else . . ?

[JosAH]

Thank you very much!

I would like also to ask what about brackets

How can I reaplace with something else . . ?

I'm sorry, I don't understand your question; brackets and parentheses can be
escaped by backslashes but I don't know if that's what you're looking for.

kind regards,

Jos

[pro]

I'm sorry, I don't understand your question; brackets and parentheses can be
escaped by backslashes but I don't know if that's what you're looking for.

kind regards,

Jos

I found it, is
cleanString = cleanString.rep laceAll("[\\)\\(\\[\\]]", " $0 ");

But I didn't understand how can I replace strings that I don't care if the characters are little or big.
I mean That's,that's,T hAT's to be all the same.

replaceAll("... ",)????

[JosAH]

I found it, is
cleanString = cleanString.rep laceAll("[\\)\\(\\[\\]]", " $0 ");

But I didn't understand how can I replace strings that I don't care if the characters are little or big.
I mean That's,that's,T hAT's to be all the same.

replaceAll("... ",)????

Read about all the posibilities in the Pattern API documentation; maybe a
simple \w will do for your purpose or a POSIX character class ...

kind regards,

Jos

[prometheuzz]

I would like the same for the expression

cleanString = cleanString.replaceAll("That's", " That is ");
cleanString = cleanString.replaceAll("that's", " that is ");

Try something like this:

String s1 = "ThAt'S it!";
String s2 = s1.replaceAll("[T|t][H|h][A|a][T|t]'[S|s]", "That is");

Details:

http://java.sun.com/j2se/1.5.0/docs/api/java/util/regex/Pattern.html