Clarify the associativity

[vensriram]

int i=-3,j=2,k=0,m;
  m=++i||++j&&++k;
  printf("\ni=%d""\nj=%d""\nk=%d""\nm=%d",i,j,k,m);

FOR THE ABOVE CODE my compiler gives the answer as
i=-2, j=2, k= 0, m=1

At first ++i||++j is evaluated. For the || operator if one operand is non-zero the result is non-zero.hence here i is increased to -2 and ++j is not evaluated...

But after this -2 should be ANDed with k. Since for the && operation both the operands should be evaluated to find the result according to me K should be increased to 1. But here the K is not increased. Kindly clarify the reason pls

[newb16]

No. With parentheses, the expression is
m=++i||(++j&&++ k);
First, ++i is evaluated. As it is nonzero, the result of || operation is true (1) and the rest is not evaluated at all (short-circuit evaluation). i gets incremented to -2 and the other are not changed.

[vensriram]

Thanks for your reply. But here the expression will be evaluated from left to right(imagine the condition without paranthesis) and hence I doubt the AND operation should take place.Kindly clarify

[newb16]

Parentheses make no difference as && has higher precedence than || , so they evaluate left to right, evaluating the left argument of || first, then (is if was 0) its right argument, which is ++j && ++k , not ++j alone.

[vensriram]

Thanks newb16.......i have understood it clearly....