Code:
void *print_message(int *i1)
'void* (*)(int*)' to 'void* (*)(void
*)'
to take an argument of void*
newb16
Last Activity: Jan 27 '12, 07:22 AM
Joined: Jul 9 '08
Location:
-
You have it declared
and compiler expects it
'void* (*)(int*)' to 'void* (*)(void
*)'
to take an argument of void* -
Windows 7 will not allow you (a non-elevated app) to create file in the root of the disk.Leave a comment:
-
They are not null, they are assigned something.
FrameImage = cvQueryFrame(Ca pture);
MirrorImage = cvCloneImage(Fr ameImage);
The other thing is that you never free/release them after you process them.Leave a comment:
-
No memory leak, but the Feature(); call doesn't call the Feature() constructor of 'this' object but creates a new Feature object that is destroyed when it leaves the scope.Leave a comment:
-
I tried it with printf("this %d\n", this); inserted in both constructors and it shows that your constructor call creates new, another Feature object and then discards it.Leave a comment:
-
this
.... here 'one' is an object of struct type 'box'
and this...
I declared an array of struct type 'box' (size=12) , named it 'one', ...
are different things. The first one has the member 'no' that can be accessed as one.no ; the second is an array and has to be accessed like
one[1].noLeave a comment:
-
use constructor initializers list:
Triangle::Trian gle(Vertex & one, Vertex & two, Vertex & three) {
: v1(one)
, v2(two)
{
// the rest of constructor
..Leave a comment:
-
I entered all ones for all questions and it was ok.Leave a comment:
-
If you open in in visual studio, programmer's notepad or any other editor that can match braces, you will see that
this
}//program ends
actually pairs with open brace at line 5106.Leave a comment:
-
There must have been line numbers along the error codes?
-> p_arr[m]
You can't index pointers of type void. Compiler has no information during compile time about the nature of data the void* points to. Cast it to some pointer type you know, e.g.
((float*)p_arr)[m]Leave a comment:
-
It may not matter who is logged in, but what under user your process is running.
Find the user the process is running under and then find if it belongs to administrators group? Then search for functions to do this on microsoft site, starting e.g. from here http://msdn.microsoft.com/en-us/libr...(v=VS.85).aspx
Googled a bit more ... -
OpenProcess (PID) -> process handle
OpenProcessToke n (process handle) ->...Leave a comment:
-
at this moment, cpp was advanced to point to cp[2], so cpp[-2] points to cp[0] that holds value c+3, pointer to "FIRBE".Leave a comment:
-
Fullscreen - no, there is no text mode fullscreen for console applications in Vista/W7. You can set larger font size in window properties.Leave a comment:
-
newb16 replied to Under what conditions is it impossible to put an inspector method in a source file?in C'const' after argument list is a part of declaration and must be present in .cpp as well
bool inspectionExamp le::hasThisInt( int const inputInt ) const
{
...
}Leave a comment:
-
This will generate something likeCode:void printlog(int left, int right) { if (left==right) { printf("%d", left); return; } int m = (left+right)/2; printf(" ( (i)>=%du)?", 1<<(m+1)); printlog(m==right?m:m+1,right); printf(" : "); printlog(left, m); } printlog(0, 5);
( (i)>=8u)?...Leave a comment:
-
If the specification of the structure says something like 'on position 11 and 12 there is a 16-bit value'( yes it does - http://en.wikipedia.org/wiki/Fat16#Boot_Sector ) you need to manually extract them from the raw data, like
unsigned short bytesPerSector = raw[12] << 8 | raw[11];
Hoping that a compiler propery align it is not reliable. Endianness also matters.Leave a comment:
-
It may as well expect something like this
Code:char *a="abcd"; char*b = "dcba"; char *s[2] = {a,b}; some_function(s);Leave a comment:
-
If it's a part of some framework written in Obj-C, you can't use it in a pure C++ code.Leave a comment:
-
just replace all console i/o operators with corresponding printf and scanf.Leave a comment:
-
because, say, 3 <= 1 <= 4 evaluates to
(3<=1) <= 4 then to
0 <= 4 that is true. Use || and && for multiple conditions.Leave a comment:
No activity results to display
Leave a comment: