Status of post: Unsolved!!! - type conversion problem that needs help C++

[slizorn]

hi guys,
the error is as follows:
error C2440: '=' : cannot convert from 'TreeNode<T> *' to 'char *'
with
1> [
1> T=char
1> ]
1> Types pointed to are unrelated; conversion requires reinterpret_cas t, C-style cast or function-style cast

i get this error from the following line of code:

assign = searchTree(treeObj->root ,data1);

which is part of the following method

void handleOneLine(string string1)
{
	char * cstr, *p, *assign;
	int counter;
	string str (string1);
	char data1, data2, data3;

	cstr = new char [str.size()+1];
	strcpy (cstr, str.c_str());

	// cstr now contains a c-string copy of str

	int count = 0;
	p=strtok (cstr,",");
	count++;
	while (p!=NULL)
	{
		p=strtok(NULL,",");
		if( count == 1 )
		{			
			data1 = *p;
			assign = searchTree(treeObj->root ,data1);
			treeNodeObj->item = new TreeNode();
		}
		else if( count == 2 )
		{
			data2 = *p;
//			treeNodeObj->setLeft(data2);
		}
		else if( count == 3 )
		{
			data3 = *p;
//			treeNodeObj->setRight(data3);
		}
		count++;
		if( count == 3 )
			break;
	}

	delete[] cstr; 
}

the searchTree method is below

#include <iostream>
#include <fstream>
#include <string>
#include <queue>
#include <deque>
#include "TreeNode.h"
#include "Tree.h"
using namespace std;

Tree<char> *treeObj = NULL;
TreeNode<char> *treeNodeObj = NULL;

TreeNode<char>* searchTree(TreeNode<char> *cur, char nodeToAdd)
{
	if(cur == NULL) 
	{
		return NULL;
	}
	if(cur->IsSameNode(nodeToAdd))
	{
		return cur;
	}
	searchTree(cur->getLeft(), nodeToAdd);
	searchTree(cur->getRight(), nodeToAdd);
}

could you please help me with this?
i will reply within 5 mins so plz do check back if u require anything else e.g. code or a qn answered.
thanks :)

i have included the TreeNode file below just in case:

#pragma once
#include <iostream>
#include <fstream>
#include <string>
#include <deque>
#include <queue>
using namespace std;

template <class T>
class TreeNode
{
	public:
		TreeNode<T>(T newItem);
		~TreeNode<T>(void);
		void setItem(T *newItem);
		void setLeft(TreeNode *newLeft);
		void setRight(TreeNode *newRight);
		T getItem();
		TreeNode<T>* getLeft();
		TreeNode<T>* getRight();
		bool IsSameNode(T c);
		T item;

	private:
		TreeNode *left;
		TreeNode *right;
};


template <class T>
TreeNode<T>::TreeNode(T newItem)
{
	item = newItem;
	left = null;
	right = null;
}

template <class T>
TreeNode<T>::~TreeNode(void)
{
}


template <class T>
void TreeNode<T>::setItem(T *newItem) 
{
	// set methods
	item = newItem;
}

template <class T>
void TreeNode<T>::setLeft(TreeNode *newLeft) 
{
	left = newLeft;
}

template <class T>
void TreeNode<T>::setRight(TreeNode *newRight) 
{
	right = newRight;
}

template <class T>
T TreeNode<T>::getItem()
{
	// get methods
	return item;
}

template <class T>
TreeNode<T>* TreeNode<T>::getLeft() 
{
	return left;
}

template <class T>
TreeNode<T>* TreeNode<T>::getRight() 
{
	return right;
}

template <class T>
bool TreeNode<T>::IsSameNode(T c)
{
	return this->item == c;
}

[slizorn]

please feel free to ask me any qns or suggest any suggestions.. i am up for anything.. thanks :)

[boxfish]

Hi,
I'm not sure this is helpful, but here it is anyway.
Your compiler is complaining because the searchTree function returns a TreeNode<char>* , and you can't assign that to a variable of type char*.
I didn't look at your code very carefully, but maybe you meant assign to be of type TreeNode<char>* , like this:

TreeNode<char>* assign;
assign = searchTree(treeObj->root ,data1);

or maybe you meant to assign to be of type char, and to use the TreeNode's item variable:

char assign;
assign = searchTree(treeObj->root ,data1)->item;

Well, I hope this is somewhat helpful. Good luck.

[slizorn]

Hi,
I'm not sure this is helpful, but here it is anyway.
Your compiler is complaining because the searchTree function returns a TreeNode<char>* , and you can't assign that to a variable of type char*.
I didn't look at your code very carefully, but maybe you meant assign to be of type TreeNode<char>* , like this:

TreeNode<char>* assign;
assign = searchTree(treeObj->root ,data1);

or maybe you meant to assign to be of type char, and to use the TreeNode's item variable:

char assign;
assign = searchTree(treeObj->root ,data1)->item;

Well, I hope this is somewhat helpful. Good luck.

yup it was cheers! :)