How to implement sizeof operator in C

[maheshgupta024]

Can anyone tell me how to implement sizeof in C language

[r035198x]

Can anyone tell me how to implement sizeof in C language

There already is an implemenation of it. Do you want to use it or to create your own?

[maheshgupta024]

yes.. I want to write a function which provide the same functionality.. .

[Banfa]

Since you can not write a function that takes a type as an argument you will not be able to do what you wish.

You can get the size of a type programatically but the code would have to be specific to the type.

The sizeof operator exists because there is no real other way to get the functionality it provides and it is something that is useful.

[oler1s]

sizeof is a compile time operator. Asking how to implement sizeof only makes sense if you are writing your own compiler.

[AmberJain]

The link below may help you out more------>

LINK

HOPE THIS HELPS.......... .....

============
AmbrNewlearner
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[JosAH]

The link below may help you out more------>

LINK

All it does is show you that a sizeof operator is a compile time operator and
necessarily highly platform dependent. That is/was an interesting thread: I
didn't know that some of my compadres had posted in this forum ...
I think it's just a temporary tap from a usenet feed though.

kind regards,

Jos

[r035198x]

..That is/was an interesting thread: I
didn't know that some of my compadres had posted in this forum ...

A macro that gets the address, adds 1 and subtracts that address would be very close.

[JosAH]

A macro that gets the address, adds 1 and subtracts that address would be very close.

Only partly; there are two forms of the sizeof operator:

1: sizeof ( type-name )
2: sizeof unary-expression

your suggestion only works for the first alternative but what would the size be
of, say '~(a+b++)'? It can't be done without being part of the compiler and knowing
about the platform this darn thing is executed on.

kind regards,

Jos

[r035198x]

Only partly; there are two forms of the sizeof operator:

1: sizeof ( type-name )
2: sizeof unary-expression

your suggestion only works for the first alternative but what would the size be
of, say '~(a+b++)'? It can't be done without being part of the compiler and knowing
about the platform this darn thing is executed on.

kind regards,

Jos

Hence the "close".
BTW Have you implemented sizeof in .... <starting to get out of topic here so I'll stop>.

[JosAH]

Hence the "close".
BTW Have you implemented sizeof in .... <starting to get out of topic here so I'll stop>.

Try 'abs'

kind regards,

Jos

ps. sorry for being off-topic.