Function argument error?

[mosullivan]

I don't know where the problem with my program is. I keep getting an error that says the function doesn't take 1 argument. I have two arguments listed for the function everytime I mention it. The error is said to be in line 46. Any help would be great.

#include <stdio.h>

int total(int hi, int count);

int main (int)
{
	int n;		/*Input by the user*/
	int m;		/*Input by the user*/
	int lo;		/*Assigned the lower number*/
	int hi;		/*Assigned the higher number*/
	int count;

	/*Prompt the user to input 2 numbers*/

	printf("This program will add the range of numbers entered.");

	printf("\n\nEnter the low number and the high number.\n\n");

	/*Accept the user input*/

	scanf("%d%d", &n, &m);

	/*Determines the hi and lo*/

	lo = (n < m) ? n : m;		/*Assigns the lower number to lo*/
	hi = (n > m) ? n : m;		/*Assigns the higher number to hi*/

	count = (hi - lo) + 1;		/*Counts the total number of numbers in range*/
	
	/*Call function*/

	total(hi, count);
	
	printf("\nThe sum of the range of numbers %d and %d is %d.\n\n", lo, hi, total(hi, count));

	
}

#include <stdio.h>
int total(int hi, int count)

{ 
	if (count == 1)
		return (hi + 1);
	else
		return (hi + total(hi - (count - 1)));
		
}

[scruggsy]

int total(int hi, int count);

...

return (hi + total(hi - (count - 1)));

You're calling total(), which takes 2 arguments, with only 1 argument.
hi - (count - 1) is only one argument.

[mosullivan]

Ok, I understand that. I've changed it so that count is a function and now I'm getting an error that says 'lo' is an undeclared identifier. Both hi and lo are identified in the main - is there something I'm missing?

#include <stdio.h>

int total(int hi);
int count(int hi, int lo);

int main (int)
{
	int n;		/*Input by the user*/
	int m;		/*Input by the user*/
	int lo;		/*Assigned the lower number*/
	int hi;		/*Assigned the higher number*/
	

	/*Prompt the user to input 2 numbers*/

	printf("This program will add the range of numbers entered.");

	printf("\n\nEnter the low number and the high number.\n\n");

	/*Accept the user input*/

	scanf("%d%d", &n, &m);

	/*Determines the hi and lo*/

	lo = (n < m) ? n : m;		/*Assigns the lower number to lo*/
	hi = (n > m) ? n : m;		/*Assigns the higher number to hi*/

	count(hi, lo);
	
	/*Call function*/

	total(hi);
	
	printf("\nThe sum of the range of numbers %d and %d is %d.\n\n", lo, hi, total(hi));

	
}
#include <stdio.h>

int count(int hi, int lo);
int total(int hi)

{ 
	if ((count(hi, lo)) = 1)
		return (hi + 1);
	else
		return (hi + total(hi - ((count(hi, lo) - 1))));
		
}
#include <stdio.h>

int count(int hi, int lo)
{
	int cnt = 0;

	cnt = (hi - lo) + 1;		/*Counts the total number of numbers in range*/

	return 1;
}

[Ganon11]

What is that mess at the end? You are #include <stdio.h> three times, and you declare count twice before defining. There's no need for the extra definitions and #includes after the top of the program. Anyway, your problem is in total - you use count(hi, lo), but you never got lo from main, only a variable named hi as an argument.

[mosullivan]

What is that mess at the end? You are #include <stdio.h> three times, and you declare count twice before defining. There's no need for the extra definitions and #includes after the top of the program. Anyway, your problem is in total - you use count(hi, lo), but you never got lo from main, only a variable named hi as an argument.

The mess are the two functions. I guess I should have titled them so I didn't cause any confusion. I'll look at total again. Thanks

[mosullivan]

The mess are the two functions. I guess I should have titled them so I didn't cause any confusion. I'll look at total again. Thanks

I started over and have completed the assignment. Thanks for all your help.