Invalid conversion from 'int*' to 'int' question

[Nozdormu]

Hi guys, I have a quick question. The language I'm using is C.

The question I'm tackling:
Write a program that
(1) defines a 1D array with ten int elements, and
(2) sets the values of the elements such that they are equal to the addresses of the elements, and
(3) prints out the content of the elements.
The program should call a user-defined function value_address with the following function prototype: void value_address( int[] )

My answer:

[CODE=c]#include <stdio.h>
int main(void)
{
int array[10], i;
void value_address(i nt[]);

value_address(a rray);

for (i=0;i<10;i++)
printf("Value of array[%1d] is %d\n", i, array[i]);

return 0;
}

/* function definition for value_address */
void value_address(i nt inarray[])
{
int i;
for (i=0;i<10;i++)
inarray[i] = &inarray[i];
}[/code]


I'm getting an error message Invalid conversion from 'int*' to 'int' on the line below
inarray[i] = &inarray[i];
What am I doing wrong?

Thanks :)

[JosAH]

Write a program that
(1) defines a 1D array with ten int elements, and
(2) sets the values of the elements such that they are equal to the addresses of the elements, and
(3) prints out the content of the elements.
The program should call a user-defined function value_address with the following function prototype: void value_address( int[] )

[ ... ]

I'm getting an error message Invalid conversion from 'int*' to 'int' on the line below
inarray[i] = &inarray[i];
What am I doing wrong?

Thanks :)

You're not doing anything wrong: question 2) sucks, i.e. an int can't contain an
address because ints are not guaranteed to be able to contain the value of an
int* (a pointer to an int).

kind regards,

Jos