Boolean problem

[anorisml]

Hi guys! I would like to know if anyone can help me with this:
i must make a difference between two variables ('t' and 'o') which are both boolean: t-0. i don't know how i can do it, and i would appreciate if anyone could help me. the language is C++.
thanks
anoris

[khosrow]

what do you mean by "making a diffrence" ?

[anorisml]

what do you mean by "making a diffrence" ?

sorry the "bad language"
a quantity minus outher.somethin g like the mathematical subtraction:
5-3=2

[Ganon11]

If your variables are both booleans, then you have a few possibilities:

T and O are both TRUE. C++ represents TRUE as 1, so you will have 1-1 = 0, which is interpreted as FALSE.

T and O are both FALSE - this is 0-0 = 0 which is FALSE.

T is TRUE and O is FALSE, then you have 1-0 = 1 which is TRUE. Alternatively, if T is FALSE and O is TRUE, then you have 0-1 = -1 which I think is also TRUE.

[Laharl]

Alternatively, if T is FALSE and O is TRUE, then you have 0-1 = -1 which I think is also TRUE.

-1 should be TRUE, since 0-1 is equivalent to 1-0 in truth value, as the - basically represents an OR relationship.

[anorisml]

Yes, I know all of that, but what I really wanted to know was how to do it in C++. I will need that result to do other things. Meanwhile I spoke to a colleague of mine which said that I could do the code like this:

bool g, t, o;
(...)
g=t^o;

and the result, g, would always give me the expected value. I checked, and, as a matter of fact, the result that appears is always what it should give. What I would now like to know is if this is a correct way of doing it, or if any problem will come out of this. If anyone knows anything about this, than I would be really appreciate.
Anoris

[JosAH]

Yes, I know all of that, but what I really wanted to know was how to do it in C++. I will need that result to do other things. Meanwhile I spoke to a colleague of mine which said that I could do the code like this:

bool g, t, o;
(...)
g=t^o;

and the result, g, would always give me the expected value. I checked, and, as a matter of fact, the result that appears is always what it should give. What I would now like to know is if this is a correct way of doing it, or if any problem will come out of this. If anyone knows anything about this, than I would be really appreciate.
Anoris

There is no arithmetic '-' (minus) defined for a Boolean algebra; the 'difference'
of two boolean values could be defined as 'a^b', what you did, and it is equivalent
to 'a != b' which maybe looks less cryptic.

kind regards,

Jos