question about printf

[Hiral]

what is the output of

void main()
{
printf("%d");
}

[RedSon]

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[RedSon]

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[Savage]

The output will be ZERO


Savage

[nmadct]

what is the output of

void main()
{
    printf("%d");
}

Try it and find out!

[sicarie]

The output will be ZERO


Savage

Umm, I'm pretty sure that's incorrect. Did you try running it?

[Savage]

Umm, I'm pretty sure that's incorrect. Did you try running it?

Yes,I runed it and it gaved me a 0.

Savage

[Banfa]

The output could be anything, it invokes undefined behaviour on at least 2 counts.

[Ganon11]

The output could be anything, it invokes undefined behaviour on at least 2 counts.

Let me guess:

1) void main() instead of int main()
2) printf("%d"); is supposed to print an integer value, but no such value is specified.

[chella]

Hi,
The value of the statement printf("%d") varies depending on the compiler we use.
In Unix, cc compiler will produce a result as some unknown integer value.
In Turbo C compiler the result will be zero.

This depends on the compiler which we use


Regrads,
Chella

[JosAH]

Hi,
The value of the statement printf("%d") varies depending on the compiler we use.
In Unix, cc compiler will produce a result as some unknown integer value.
In Turbo C compiler the result will be zero.

This depends on the compiler which we use


Regrads,
Chella

My compiler makes daemons fly out of your nose. As said before: calling the
printf function like this causes undefined behaviour. Every (educated?) guess
what the output would/could be is just guessing. Nothing can be said about it.

kind regards,

Jos

[Banfa]

1) void main() instead of int main()
2) printf("%d"); is supposed to print an integer value, but no such value is specified.

That is what I was thinking of :D