Truncating Strings--an Expert needs novice help!

[RedSon]

Here is the problem:

I have a path to a file like \Windows\Start Menu\Accessorie s\Calculator.ln k and I am trying to truncate it down to just "Calculator ".

_tcscpy(pItem->label, recentItem->path);
*wcsrchr (pItem->label, '.') = '\0';

First I am copying the recentItem (which is just a struct that has a TCHAR array called path -- which is the path to the shortcut) path to the pItem (which is just a struct that my WinMain method uses to populate a popup menu, that contains a label and a path -- where label is like "Calculator "). Then I truncate the label to remove the .lnk, so I am left with \Windows\Start Menu\Accessorie s\Calculator. Now I want to get rid of everything up to the last back-whack. Any ideas? I'm using all Win32 stuff here.

[Ganon11]

You have the path in a string/character array, correct?

Then just search backwards through the array for the 'first' occurrence of the \ character - this will be the position of the last \ character in the string. Then get the substring from that position + 1 to the end of the string.

[RedSon]

You have the path in a string/character array, correct?

Then just search backwards through the array for the 'first' occurrence of the \ character - this will be the position of the last \ character in the string. Then get the substring from that position + 1 to the end of the string.

Right, but what is the methods for that?

[Ganon11]

Assuming your path is in a string called fpath,

int position;
for (int i = fpath.length() - 1; i >= 0; i--) {
   if (fpath[i] == '\\') // Because \ is escape sequence generator, and \\ is required to print \
      position = i;
      break;
   }
}

// Position now holds the location of the last '\' in fpath.
fpath = fpath.substr(position + 1);

Since you don't want to include the \ in your new filepath, you add 1 to the position is in in to get the entire string after it.