help with a floor program

[elsa]

hi
i have a question..
An application of function floor ia rounding a value to the nearest integer. the statement y=floor(x+0.5); rounds the number x to the nearest integer and assigns the result to y. how can we write a program that reads several numbers and uses the preceeding statement to round each of these numbers to the nearest integer. for each number proceeded, print both the original number and the rounded number.

[Ganon11]

And your question is...?

[elsa]

how can we write a program that reads several numbers and uses the preceeding statement to round each of these numbers to the nearest integer?

[horace1]

how can we write a program that reads several numbers and uses the preceeding statement to round each of these numbers to the nearest integer?

you could have a loop which reads the value of x from the keyboard, calculates y using y=floor(x+0.5); and prints x and y

[elsa]

i have tried this..but it is not working
#include <iostream>
# include<math.h>

using std::cout;
using std::cin;
using std::endl;

//declaration of function
double floor(double);

int main()
{
unsigned long a;
do
{
cout<<"Rounding to the nearest integer"<<endl;
cout<<"Please enter a decimal btween -100 and 100 "<<endl;
cin>>a ;
floor(a);
}while(a>=-100|| a<=100);
cout<<"you choose to quit\a\a\a"<<en dl;
return 0;
}
//definition of function

double floor (double a)
{
a=floor(a+0.5);
cout<<"the floor of the number "<<a<<" is "<<a<<endl;
return a;
}

[horace1]

you cannot call your function the same name as the floor() in the maths library. Change its name - also should the variable a that you read in be a double rather than an int?

[elsa]

i changed its name..but still it is not working..and i didnt get the second part of what u said about changing a into a double rather than the int..where is that? plz help me..im going crazy with this c++..lol

[horace1]

i changed its name..but still it is not working..and i didnt get the second part of what u said about changing a into a double rather than the int..where is that? plz help me..im going crazy with this c++..lol

I assume you want to convert a real value (with a fractional component) to the nearest integer, which is what floor(a+0.5) does.
see if this does what you require

#include <iostream>
# include<math.h>

using std::cout;
using std::cin;
using std::endl;

//declaration of function
double myfloor(double);

int main()
{
double a;  // ** make double
do
{
cout<<"Rounding to the nearest integer"<<endl;
cout<<"Please enter a decimal btween -100 and 100 "<<endl;
cin>>a ;
myfloor(a);
}while(a>=-100|| a<=100);
cout<<"you choose to quit\a\a\a"<<endl;
return 0;
}
//definition of function

double myfloor (double a)
{
double b=floor(a+0.5);
cout<<"the floor of the number "<<a<<" is "<<b<<endl;
return b;
}

when run it gives (user input in bold)
Rounding to the nearest integer
Please enter a decimal btween -100 and 100
67.3
the floor of the number 67.3 is 67
Rounding to the nearest integer
Please enter a decimal btween -100 and 100
67.7
the floor of the number 67.7 is 68
Rounding to the nearest integer
Please enter a decimal btween -100 and 100

[elsa]

thx alot for ur help..but i wanted to ask u something..why is the program not stopping when i write 100 or -100? i need to solve this problem..

[LSB]

thx alot for ur help..but i wanted to ask u something..why is the program not stopping when i write 100 or -100? i need to solve this problem..

I think it may be that sign "=" in your "while" statement, right?

[elsa]

oh yes..lol..im so crazy today..thx alot for ur help..

[elsa]

i should have written &&(and) instead of ||(or)..