pointers to variable

[Saba]

Create a program that declares an integer array with five elements. Now store in that integer array five different elements (10, 20, 30, 40, 50) using a pointer variable only.

Hints

The identifier of an array is equivalent to the address of its first element, as a pointer is equivalent to the address of the first element that it points to.

If A [5] is an array then the expressions A[2] and *(A+2) designate the same thing. Use (*A+2) to store the value in the third element of array.


Solution
#include <iostream.h>

main()
{

int A[5]= {10, 20, 30, 40, 50};
int i;

int * Aptr = A;

for( i=0; i<5; i++)
{
cout << "(*A+" << i << ")=" << A[i] << '\n';
}

}

is it correct???????? ???????????

[Ganon11]

Create a program that declares an integer array with five elements. Now store in that integer array five different elements (10, 20, 30, 40, 50) using a pointer variable only.

Hints

The identifier of an array is equivalent to the address of its first element, as a pointer is equivalent to the address of the first element that it points to.

If A [5] is an array then the expressions A[2] and *(A+2) designate the same thing. Use (*A+2) to store the value in the third element of array.


Solution

#include <iostream.h>

main()
{

  int A[5]= {10, 20, 30, 40, 50};
  int i;

  int * Aptr = A;

  for( i=0; i<5; i++)
   {
     cout << "(*A+" << i << ")=" << A[i] << '\n';
   }

}

is it correct???????? ???????????

Take a look back at your problem specification. After you have initialized the array of 5 values, you are asked to store the 5 elements using a pointer variable only. From your code, you use Aptr only once - when you declare it!

Instead, why not use a pointer from the start? As I'm new to C++ and don't have a book handy, I'm not sure of the syntax for this, but I know you can do it. Then, individually set each value of the array as your hint tells you: by using the statement *(A+i) = num, replacing i with whatever position needed (0-4) and replacing num with the appropriate value.

[Banfa]

int A[5]= {10, 20, 30, 40, 50};

This is an array initialisation, you are told to only declare an array like this

int A[5];

The values stored in the array should be set using your pointer

int * Aptr = A;

[kenx125]

Create a program that declares an integer array with five elements. Now store in that integer array five different elements (10, 20, 30, 40, 50) using a pointer variable only.

Hints

The identifier of an array is equivalent to the address of its first element, as a pointer is equivalent to the address of the first element that it points to.

If A [5] is an array then the expressions A[2] and *(A+2) designate the same thing. Use (*A+2) to store the value in the third element of array.


Solution
#include <iostream.h>

main()
{

int A[5]= {10, 20, 30, 40, 50};
int i;

int * Aptr = A;

for( i=0; i<5; i++)
{
cout << "(*A+" << i << ")=" << A[i] << '\n';
}

}

is it correct???????? ???????????

Ok here is the code you require.


#include <iostream>
using namespace std;


int main()
{
int Array[5];// Declaring an array to hold 5 intergers.
int *p, num, i;
p=Array;


for(i=0; i<5;i++)
{

cout <<"Enter num :"<<(i+1)<<endl ;
cin>>num;
*(p+i)=num;
}

for(i=0; i<5;i++)// To print contents of array
{
cout<<*(p+i) <<" ";

}

system("PAUSE") ;
return 0;
}