How to Save and Retrive image?

[nur alam]

using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Windows.Forms;
using System.IO;
using System.Drawing.Imaging;

namespace WindowsFormsApplication1
{
    public partial class Form1 : Form
    {
        public Form1()
        {
            InitializeComponent();
        }

        private void button1_Click(object sender, EventArgs e)
        {
            MemoryStream stream = new MemoryStream();
            pictureBox1.Image.Save(stream, ImageFormat.Jpeg);
            byte[] memImageData = stream.ToArray();

        }

        private void button2_Click(object sender, EventArgs e)
        {
OpenFileDialog OpenFileMemPhoto = new OpenFileDialog();
OpenFileMemPhoto.Title = "Open File";
OpenFileMemPhoto.Filter = "All files (*.*)|*.*|All files (*.*)|*.*";
OpenFileMemPhoto.FilterIndex = 2;
OpenFileMemPhoto.RestoreDirectory = true;
if (OpenFileMemPhoto.ShowDialog() == DialogResult.OK && OpenFileMemPhoto.FileName != null)
            {
txt_mem_image_address.Text = OpenFileMemPhoto.FileName;
                pictureBox1.Load(OpenFileMemPhoto.FileName);
            }
        }
    }
}

The error is:

A generic error occurred in GDI+.


Please give me solutions if any.......

[GaryTexmo]

Can you please be a little more descriptive about where the problem occurs? Does it happen in button1's click event handler, or button2's?

I've seen this error before (though under slightly different circumstances) and I know the exception gets thrown at the application level. When I saw it the cause was closing a memory stream that I had loaded an image from. This case looks somewhat different but lets be sure of what's going on before I try to start helping you out :)

[nur alam]

I have used the following line and problem solved.

pictureBox1.Ima ge = new Bitmap(OpenFile MemPhoto.FileNa me);


thank you for your reply

[GaryTexmo]

Keep in mind that when you do that, an open file handle is left on the file... this isn't always undesirable, just something to be aware of.

(Loading an image into a memory stream to make a copy is a way to work around this, which is what I thought you were doing :D)