what is happening with my program output

[alireza6485]

I run the following code

Code:

int i;
int j=2
i=j+3
int k=i/2
k++
k=i*j+1
Console.Write.....
Console.Write.....
Console.Write.....
i=j<<2
Console.Write....
int L=k+1
j=j+1
k=i*j+1
Console.Write...
Console.Write...
Console.Write...
Console.Write...

and i get

i=5
j=2
k=11

i=8

i=8
j=3
k=25
l=12

Please let me know what is happening in this program,how do i get k=2 when k=i/2???
where is i=8 coming from???

[Plater]

This line:
i=j<<2
It moves i up by two bit positions, so since j=2, then after this line i=8

0000 0010 => 0000 1000

[code=c#]
int i;
int j = 2;

i = j + 3;//i=5
int k = i / 2;//k=2
k++;//k=3
k = i * j + 1;//k=11
Console.WriteLi ne("i=" + i.ToString());
Console.WriteLi ne("j=" + j.ToString());
Console.WriteLi ne("k=" + k.ToString());
i = j << 2;//i=8
Console.WriteLi ne("i=" + i.ToString());
int L = k + 1;//L=12
j = j + 1;//j=3
k = i * j + 1;//k=25
Console.WriteLi ne("i=" + i.ToString());
Console.WriteLi ne("j=" + j.ToString());
Console.WriteLi ne("k=" + k.ToString());
Console.WriteLi ne("L=" + L.ToString());
/*
//and i get
i = 5;
j = 2;
k = 11;

i = 8;

i = 8;
j = 3;
k = 25;
l = 12;
*/
[/code]

[snegulko]

k = i / 2
at that line u get k = 2 because k is defined as an int somewhere upper in your code and that means when u get a value that is not int by "/" it gets the number without the decimals. Converts it itself to int.

[kunal pawar]

You can debug code. Which help you what happen in code.