sir i think this is how the steps will go,but can u explain me your logic in steps (1) & (2)


x = 3;
x = x - (--x - x--)
x = x - (--(3) - x--)
x = x - (2 - x--)
x = x - (2 - (2)--)
x = x - (2 - 1) /* (sir according to postfix operation) */ .. (1)
x = (2) - 1 (2)
x = 2-1
x...