In your code.
Code:
scores[i] = value;
if (scores[i] == value)
{
dupe = 1;
}
In the code
Code:
if (dupe != 1)
{
DavidJones
Last Activity: Nov 14 '06, 03:52 AM
Joined: Nov 3 '06
Location:
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Hi,
In your code.
if statement will always return true because you are assigning value to scores[i] in the previous statement. So this doesnt seems correct.
In the code
... -
check this link...
http://www.phptr.com/articles/article.asp?p=3 1783&seqNum=4&r l=1
~DavidLeave a comment:
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Global variables are stored in data segment of memory whereas local variables are stored in stack memory.
~DavidLeave a comment:
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Hi,
Use modulus operator, %. It computes the remainer that results from performing integer division.
if(number % 2 == 0) => number is even
else number is odd.
~DavidLeave a comment:
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Hi,
This function should work...
...Code:#include <stdio.h> #include <stdlib.h> //function declaration char *mystrcat(char *s, char *p); int main() { printf("%s",mystrcat("David","Jones")); } //function defination char *mystrcat(char *s, char *p) { static int k;Leave a comment:
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Hi,
Try this code...
...Code:#include <stdio.h> int main() { char str[] = "The quick brown fox jumps over the lazy dog" ; int i,prev,w_len; prev = w_len = 0; for(i=0;i<sizeof(str);i++) { if(str[i] == ' ' || str[i] == '\0' ) { w_len = (i - prev); printf("\t%d\t%d\t\n", i,w_len); prev = i +1 ; }Leave a comment:
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