mmag
Last Activity: Aug 6 '14, 07:30 AM
Joined: Feb 3 '14
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i don't understand your way.if possible you write code.are you sure this a very hard problem?i thought a lot but for per algorithm i needed to temporary string or file.this is assistant's homework.it can't very hard. -
how to remove and replace some char in a file(in c++)?
i want to remove some character in my file. too i want to replace some char to another. i know the easiest way for this job is we write final text in file. i mean we first produce sightly text then write it in file .i don't want use of temporary string.what do i do for solving this problem ? -
how to subtract two string containing numbers?
hi.i have a code for subtract of two char arrays(size of each is 50).but i want to write this program with string and i should be consider that size of each string may be not equals.for example we have s1=4777 and s2=55.and we should be subtract them.this is my code.
...Code:char* sub(char x[50],char y[50]) { int i,j,temp=0; char z[50]={'0'}; for(i=0;i<50;i++) { z[i]='0'; } for(i=49;i>=0;i--) -
my algorithm that is for per subset exists one number. these numbers are form 0 until (2^n)-1.allow me explain it with a example.
n=3
{ } 000 0
{1} 100 4
{2} 010 2
{3} 001 1
{1,2} 110 6
{1,3} 101 5
{2,3} 011 3
{1,2,3} 111 7
The third column show some number(fn) that i use in code.now we know per number of subset has to state(sn).0 or 1. this means...Leave a comment:
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show all subset of a sub
A program is a set of all subsets of this part of the show. Users can enter a number., For example, if n = 2 the output looks like this:
{}
{1}
{2}
{1,2}
or for n=3 we have:
{}
{1}
{2}
{3}
{1,2}
{1,3}
{2,3}
{1,2,3}
meantime this program should be solved with tow way.
recursive function and Non-recursive.Can also be used in solving the problem... -
How to define a dynamic 2D array
my professor said one way for declaration dynamic 2d arrays.
and i never understand this way.like what does y or x in this code.I want a person explain how works this code.if show with a image is better.thanksCode:int **a=new int *[m]; int *x=new int[m*n]; int *y=x; for(int j=0;j<m;j++) { a[j]=y; y+=n; }Last edited by Rabbit; Feb 3 '14, 08:24 PM. Reason: Please use [CODE] and [/CODE] tags when posting code or formatted data.
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