B can be 1,0,positive or negative.I have done this program.And that line
Code:
y=-y
Andrew V
Last Activity: Jun 9 '12, 02:34 PM
Joined: May 29 '12
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well,i have to do a program that will do A to the power B.
B can be 1,0,positive or negative.I have done this program.And that linei have writed it because i had no ideas how i can do it to work with negative powers.And i i erease that line the program it will not work for negative power and if i keep it it works.I want to know what that line means and why i can't do it without it. -
Yes but how can i do it without that?...Leave a comment:
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uhm...why not? if that line is there the program it will not work for negative power.Leave a comment:
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When i compiled it it gives the same result,and i think it's the same.Leave a comment:
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Explanation
Can someone explain me what thestands for inCode:y=-y;
...Code:#include<iostream.h> using namespace std; int main(){ int x, y; float product=1 ; cout << "Enter a base number: "; cin >> x; cout << "Enter an integer exponent: "; cin >> y; int i = 1; if (y<0) { y=-y;//HERE I AM while (y>=i) { product -
orCode:while(count<=-1*n){
and then what?Code:while(n<0){
how do i save a number..Leave a comment:
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Ok so i put
and then i putCode:while(n<0){
but the output doesn't stop.I am working for like 6 hours at this project.Can u give me a hint?Code:y = y*x; count--; cout<<y;Leave a comment:
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Ok,i solved with positive and 0 powers.But now i am trying to do with negative power.I want it to show :
x=2
n=-1
y=0.5
i changed the codewithCode:while ( count <= n);
but nothing happens.And when i am trying to put it with if(){} it gives the same number with the x(the base) with every number i enterCode:while ( count >= n);
Leave a comment:
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Got it.My bad i readed while and while but it was do-while and while sorryLeave a comment:
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Output wrong..
This is my code and i dont know why when i enter let's say x=3 and n=0 it gives 3.
...Code:#include <cstdlib> #include <iostream> using namespace std; int main() { printf("==========©©Andrei78©©=========="); printf("=======©All Rights Reserved©===="); -
i have done something but idk why it gives with error...
...Code:#include<iostream> using namespace std; int main() { float a, b, c, d; cout << "enter the base"; cin >> a; cout << "enter the power"; cin >> b; a=d; do{ d*a; }while(d<=b); cout<<a<<"theLeave a comment:
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A to the power B question
Hello guys,i need a program which can calculate A to the power B. Like,i input 2 and 3 and it gives 8.And i need it done with loops.Thank you for helping, -
that's it i have done it it's finished and done!! hurray!
...Code:#include<iostream> using namespace std; int main() { int input; int highest = 0; int lowest = 0; cout<< "Enter A Number (0 to stop the loop): \n"; cin >> input; highest = input; lowest = input; while(input!=0) { coutLeave a comment:
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Ok,so now i need the same program but with loop not arrays,not with anything,only loop.can anyone help me please.
oh and btw i have done that with arrays look
...Code:#include <iostream> using namespace std; int main () { int a[5],y,max; cout<<"Enter 5 numbers "<<endl; for (y=0;y<5;y++) { cin>>a[y]; if (y==0) max=a[y];Leave a comment:
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I know,i fixed it and now i understand the thing with [] they are arrays. What i am tryin to do is a program that it will say the maximum number of a given list.if you can help me i would be very thankfully.Leave a comment:
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Arrays Question
can someone explain to me what is the meaning of the right braket here
...Code:#include <iostream> using namespace std; int main () { int a[5],y,max; for (i=0;y<5;i++) { cin>>a[i]; if (y==0) max=a[y]; if (a[y]>max) max=a[]; } cout<<"max numb is:"<<max; system("pause");
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