Code:
function processServers() {
var amountOfServers = 5;
var i=1;
while (i <= amountOfServers) {
'checkServer'+i+'()';
i++;
}
}
'checkServer'+i +'()';
I need it to say
checkServer1(), then on the next loop it would...
dushkin
Last Activity: Feb 6 '12, 08:41 PM
Joined: Feb 2 '12
Location:
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Okay I have no idea how I could possibly do that, I have some new code that may be easier to understand what I mean..
instead of
'checkServer'+i +'()';
I need it to say
checkServer1(), then on the next loop it would... -
Do you know how I could avoid making it a string? From what you said it means I need it as a variable.
I searched around and found a method that apparently works, it said to use "window" and some square brackets, although I do not know how I would implement this into my script, can you help me with this please?Leave a comment:
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If you are asking "How do I make a text field invisible upon the page loading?" then instead of a plain <body> tag, use <body onload="hideFie ld()">
If your not asking that, and your asking "How do I make a text field disappear when I press the button" use the code I gave you above
<input type="button" id="hideField" onclick="hideFi eld()" />Leave a comment:
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A simple google search turned up with this link
http://www.webmasterworld.com/forum91/441.htm
In case you don't know where to look on that page, I'll paste the code onto here
...Code:<script language=javascript type='text/javascript'> function hideField() { if (document.getElementById) { // DOM3 = IE5, NS6 document.getElementById('textField').style.visibility = 'hidden'; } else {Leave a comment:
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AJAX sending wrong information - any idea why?
I have a question that you will probably be able to answer in a snap, though it has been a constant issue of mine for over a day.
With my PHP script, I produce a variable
When I try to use this variable in my AJAX script, this is the result being sent to my server -Code:var information1 = 'ip=127.0.0.1&port=80';
checkStatus.php ?information1
Now, as far as I can see, that isn't supposed...Last edited by Dormilich; Feb 5 '12, 10:07 AM. Reason: Please use [CODE] [/CODE] tags when posting code. -
Oh okay, I seem to have overused the term AJAX, I've been reading multiple tutorials on AJAX/Javascript and can't find a single one that teaches me how to;
Send one piece of data to my server, recieve a response and then send the next piece of data, this would loop until all the data has received a response from the server.
Do you have any idea of how to do the above task? The data are just stored in simple variables such...Leave a comment:
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I'm sorry I didn't clarify myself enough...
I have no AJAX code, I have no knowledge of AJAX, I posted here simply for a step in the right direction, or if someone is kind enough, some code I could work from.
I basically need -
Some partial code that tells me
A) How to tell AJAX what data to send to the server
B) How to tell AJAX to parse the data individually, sending the data one by one.Leave a comment:
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Perform one AJAX request one after another.
I'm new to the whole concept of using AJAX in my PHP scripts and I have stone-walled.
What I am looking to do is this;
Once the page loads, my AJAX script will start to send data to my server so that it can verify the data, after it recieves a response from my server of either a "0" or a "1", it then goes on to send another request to my server and wait for a response, it'll carry on doing this until...
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