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Rana Chakra
Rana Chakra
Last Activity: Dec 14 '10, 04:12 AM
Joined: Sep 14 '10
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  • Rana Chakra
    replied to How to Send Mail with account activation link after filling up registration form
    in PHP
    I am maintaining the mail function signature perfectly. But, the error is still there. I guess I have messed up something with ini_set() but not getting it. I need the total php settings or example to send the mail from my php page through my gmail account.
    Can you please help me?
    Even if I copied the code from the referred link. Still it is not working an it is giving the following error:

    Warning: mail() [function.mail]:...
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    Last edited by Rana Chakra; Dec 10 '10, 12:31 PM. Reason: missed a point

      Leave a comment:

    • Rana Chakra
      started a topic How to Send Mail with account activation link after filling up registration form
      in PHP

      How to Send Mail with account activation link after filling up registration form

      I am trying to send an automatic mail containing the account activation link to the person who is filling up the registration form after he/she clicks on Create account button. But every time it giving an error .... Warning: mail() [function.mail]: SMTP server response: 530 5.7.0 Must issue a STARTTLS command first. w42sm3532376wfh .15 in C:\wamp\www\Key West\NewRegiste r.php on line 66... can I get some help. The code I have written is as follows:...
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      • Rana Chakra
        replied to Why getting parse error in PHP at line 20?
        in PHP
        This code removed the problem....
        Code:
        <center><table border="1" bordercolor="orange">
  <tr>
	<td bgcolor="black">&nbsp</td>
	<td bgcolor="black"><font color="orange" face="verdana" size="2"><b>Job Number</b></font></td>
	<td bgcolor="black">&nbsp</td>
        ...
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        • Rana Chakra
          replied to Why getting parse error in PHP at line 20?
          in PHP
          OK got it.... <tr> and </tr> is firing for only one column...... Sorry for the sily question.
          See more | Go to post

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          • Rana Chakra
            replied to Why getting parse error in PHP at line 20?
            in PHP
            code under if is working for i%3==1 .... help

            I just want to display three columns in one row. But, when value of $i is 1 or 4, the statements under if is firing. Dont know why it is happening, and how to solve it.
            Code:
            $i=0;
   while ($row = mysql_fetch_assoc($result))
   {
    if(($i%3)==0)
    {
      echo "<tr>";
      echo "<td><input type=radio
            ...
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            • Rana Chakra
              replied to Why getting parse error in PHP at line 20?
              in PHP
              Yep.. solved the problem. I changed the code as follows:
              Code:
              $query="select * from employee where srl ='". $r."'";
$result=mysql_query($query);
while($row = mysql_fetch_assoc($result))
    {
	echo "<br><strong>Employee Name:".$row['ename'];
	echo "<br>Designation  :".$row['desig'];
	echo "<br>Department   :".$row['dept'];
              ...
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              • Rana Chakra
                replied to Why getting parse error in PHP at line 20?
                in PHP
                mysql_fetch_ass oc() expects parameter 1 to be resource.. line 58

                mysql_fetch_ass oc() expects parameter 1 to be resource at line 58... Please help
                Code:
                <?php
session_start();
if($_SESSION['UID'])
  {
   if($_SESSION['RGT'] == "R")
      header("location:NoAccess.php");
  }
else
      header("location:NoAccess.php");
$message="";
                ...
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                Last edited by Rana Chakra; Sep 20 '10, 12:41 PM. Reason: Wrong subject

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                • Rana Chakra
                  replied to Why getting parse error in PHP at line 20?
                  in PHP
                  Thanks for replying

                  Thanks to you too for paying kind attention. will come back if got stuck anywhere.
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                  • Rana Chakra
                    replied to Why getting parse error in PHP at line 20?
                    in PHP
                    SOlved it. wrote msg="...." instead of $msg="..."
                    Thanks....
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                    • Rana Chakra
                      replied to Why getting parse error in PHP at line 20?
                      in PHP
                      Modified - Now getting in Line 38

                      Code:
                      <?php
$username="root";
$password="";
$database="lko_phone";
$host="localhost";
$msg="";
mysql_connect($host,$username,$password);
@mysql_select_db($database);

if($_POST)
{
  $myusername=$_POST['unm'];
  $mypassword=$_POST['pwd'];

  $sql="SELECT
                      ...
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                      • Rana Chakra
                        started a topic Why getting parse error in PHP at line 20?
                        in PHP

                        Why getting parse error in PHP at line 20?

                        Code:
                        <?php
$username="root";
$password="";
$database="lko_phone";
$host="localhost";
$msg="";
mysql_connect($host,$username,$password);
@mysql_select_db($database);

if($_SERVER["REQUEST_METHOD"] == "POST")
{
  $myusername=$_POST['unm'];
  $mypassword=$_POST['pwd'];

  $sql="SELECT
                        ...
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