Code:
#include"stdio.h"
#include"stdlib.h"
#include"string.h"
char prefix[50];
int stack[50];
int top;
char infix[50];
char postfix[100];
int pre(char x)
{
switch(x)
{
case'+':
case'-':
return 1;
mido elnaggar
Last Activity: Jul 8 '10, 07:12 PM
Joined: Apr 25 '10
Location:
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ya i've only made the first level of c language in my field of study and here is the whole code i've made till now:
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look;my assignment project is to make a code that performs matrix calculations while the entry is as in the following example:
A = [4+3-2*3+3/2 (1+2*(2+3)/(5-4*5)-3) 4*5*2/(19+3); 2.1+3.2 2.6-6/4.1 3.2+1.5; 2 4 5]
B = [1 2 5; 5 2 2.1; 3 4 1]
C = A+B
D = A*B
E = C/D
The Calculated Value for E is:
E=
-1.3188045253055 4940000 1.1616421657009 4900000 -0.8846204118722 6370000...Leave a comment:
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the correct answer is 2 but it gives 3.6
cause it didn't take the precidence of those between brackets
all i want is amodification to operate on between brackets first and then continue....Leave a comment:
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problem using rpn
i 've done this code for converting a normal entry by user into rpn ,however this case doesn't work
1+(2+3)/5->1235/++ which gives wrong answer
the code is as follows:
...Code:#include"stdlib.h" #include"stdio.h" #include"conio.h" #include"string.h" void main() { char n[20][100]={""}; char o[100]={""}; char c[100]; -
rpn calculator
i ve done so far this code but it deals only with 1 digit numbers i dont know how to make it work for 2 or more digited no.s using atoi or atof functions
#include"stdio. h"
#include"stdlib .h"
#include"string .h"
char postfix[100];
int stack[100];
int top=-1;
void push(int x)
{
top++;
stack[top]=x;
}
int pop()
{
...
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