There's nothing wrong with your code (at least as much as you have posted).
You're probably using MS Visual C++ and have configured your project incorrectly. Be sure you create the project as a console application, not a win32 project.
rstiltskin
Last Activity: Mar 11 '17, 02:03 PM
Joined: Feb 6 '10
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It looks like you forgot to
#include <list>Leave a comment:
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rstiltskin replied to I'm getting an Expression Syntax error and I can't figure out what's wrong.... :(in CIn the definition of a function that takes an argument, you have to provide a name (identifier) for the argument as well as its type. And if you want the function to modify the value of that argument, that's the variable it should be working on, and not a local variable (one declared inside the function). So your getInformation should look like this:
...Code:int getInformation(int input) { scanf("%d",Leave a comment:
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You can use infile.tellg() to find out the position of the beginning of each line -- use it as the last statement in the loop so you'll know the position before each call to getline. Then adjust that value by the position of your search string in the line.
http://www.cplusplus.com/reference/i...istream/tellg/
By the way, your code doesn't seem to allow for the possibility that the search string might overlap the...Leave a comment:
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rstiltskin replied to Why am I recieving this error C2061: identifier 'cout' while trying to complile?in CYou omitted the control expression for the "else if" just before that cout.
...Code:else if (saleAmount > 0.00 && saleAmount <= 250.00) (shippingCharge = 5.00 + saleAmount); else if // <== error is here [error] cout << endl << endl; // output cout << name << ", your shipping charge is " << shippingCharge << endl; cout
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If you don't have the compiler, you installed the wrong Code::Blocks release. This is the one you need:
http://prdownload.berlios.de/codeblo...ingw-setup.exe
(Either one of the links on that page will give you Code::Blocks PLUS the MinGW compiler....Leave a comment:
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In C/C++, what you described is a 3 by 2 array, not 2 by 3.
Assuming you are writing the function (not trying to use a pre-existing library function), you can pass the address of the beginning of the subarray, the dimensions of the subarray, and the offset (i.e. the size of the second dimension/number of columns) of the original array. Your function can use that offset to navigate through the subarray.
So the function...Leave a comment:
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... meaning either you don't write any constructor (e.g. you use the compiler-supplied default constructor) OR you write your own default constructor.
In that sense, "default constructor" simply means a constructor that takes no arguments. It may initialize data members or perform other functions....Leave a comment:
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Not necessarily. It depends on your application.
If you don't write a constructor, the compiler supplies a default constructor which creates your object but doesn't do anything else.
If you want the member variables to be initialized, or if you want anything else done when the new object is created, then you have to write a constructor (or several constructors, depending on your requirements).Leave a comment:
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Lines 16-17 should be:
because d is the argument that you are supplying to the sqrt function.Code:x1=(-b+sqrt(d))/(2*a); x2=(-b-sqrt(d))/(2*a);
Also, in order to comply w ith the C language standard, the return value of your main function should be int, not void, i.e.:
Code:int main ()
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When you post code please use code tags so it will be easier to read.
You didn't actually ask a question, so here's a link that might help.
Multiplying a matrix by a vector is illustrated nicely in http://www.facstaff.bucknell.edu/mas...ecMultiply.htm. If you follow that example it's just a matter of looping through the array and the vector to do some simple multiplication and addition.Leave a comment:
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Thanks. I have no argument with that. I was just bothered because you seemed to be suggesting that typedef'ing an array changes the way that the compiler treats it -- in effect creating a new type rather than simply a 'nickname'.
But I have to say that this
is priceless. ;)...Leave a comment:
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I hope you don't mind my jumping in, but I'm puzzled by Banfa and donbock's posts. Should arrays be lumped together with all compound types? In Ectara's example, v is just an array of 3 floats, not a structure. Isn't it true that whenever an arrayname is passed as a function argument it is implicitly converted to a pointer ( although NOT when passed to the sizeof or addressof operators)? Isn't that required by both C and C++ standards, and not...Leave a comment:
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1. It's normal behavior. To a C++ compiler
Arr<int> pn = new int[pn.size = 10];
is equivalent to
Arr<int> pn(new int[pn.size = 10]);
In fact, you can even define an int variable with the value 5 this way
int i(5);
in C++ (but not in C).
2. Since you are using an int* to assign to a Arr object, the compiler is using the constructor as an implicit conversion operator, so yes, it's...Leave a comment:
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