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markus314 · Nov 5 '08, 11:20 PM

Or if you use python 2.6 and s is not a unicode string:

Code:

s.translate(None, string.punctuation+string.digits).lower()

which is approx. 12 times faster than a regex.

markus314 · Oct 29 '08, 11:19 PM

Hi!

I've just found this through google.

You can define:

Code:

from functools import partial
from itertools import repeat

def compose(f, g): #  also in the functional module
    def func(*args, **kwargs):
        return f(g(*args, **kwargs))
    return func

mcompose = partial(reduce, compose)
apply_n_times = compose(mcompose, repeat)

Then...

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