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wael20 · Jul 18 '08, 01:19 PM

I started my GUI in Thread, but i cannot debug it!

Code:

public ProgramTEST()
{
          ApplicationTestStart _applicationTestStart = new ApplicationTestStart();
          ThreadStart ts2 = new ThreadStart(_applicationTestStart.Run);
          Thread t1 = new Thread(ts2);
          t1.Start();
}

--------------------------------------------------------------------------

Code:

public

...

wael20 · Jul 18 '08, 08:19 AM

I cannot change anything on the GUI Software, It is Just example, that i click on this button, the problem is:

On this following line, my program stops:.

Application.Run (new MyApplicationCo ntext(new string[] {}));

or, when you write:

ProgramTEST MyTest = new ProgramTEST(); // here my program stops, tell i close the GUI!!!But i need the GUI!
MyTest.Test();

wael20 · Jul 17 '08, 02:21 PM

It is just example, a GUI will opened and than will clicked on OK button automatically

wael20 · Jul 17 '08, 07:31 AM

Just for example:
[PHP]
public class ProgramTEST
{
public ProgramTEST()
{
Application.Ena bleVisualStyles ();
Application.Set CompatibleTextR enderingDefault (false);
Application.Run (new MyApplicationCo ntext(new string[] {})); // -->This bolcks the course of the application.
}

public ControlTester buttonTester;

...

wael20 · Jul 16 '08, 03:27 PM

I need the GUI, that i started, to test it with NUnitforms...

so...
How can i back from Application.Run to place where was is called? (to test it with NUnitforms)

or, what should i do, when i must to use Application.Run ( new MyMainForm() ) to run my application?
so i can´t use this way:

MyMainForm myForm = new MyMainForm();
myForm.ShowDial og();

because my application...

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"C#" Back from Application.Run to place where was is called