Hi Dormilich
Thank you for quick reply, then how can i achive this kind of client requirment.
regard
saran
User Profile
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how to find closing node
How can i find CLOSING NODE in XSL-FO, i want to generate some text [eg:- section number ] in each </para> node.
For Ex:-
--------------XML File---------------
<list>
<item><para>Som e Text1</para></item>
<item><para>Som e Text2</para></item>
<item><para>Som e Text3</para></item>
</list>
-------------------------------------... -
I can't understand ur problem clearly. But try like this
<xsl:if text="unit[@ref]">
<xsl:value-of select="@ref"/>
</xsl:if>
<xsl:if text="lease[@ref]">
<xsl:value-of select="@ref"/>
</xsl:if>
-----------------------------------------------------------------------------------------------------...Leave a comment:
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Hi,
I can't catch u ur queries. Anyway i found some error in ur xml. I list here for ur reference.
Element bodytype, colour & photo not be declared.
Like this
<!ELEMENT bodytype #PCDATA)>
<!ELEMENT colour #PCDATA)>
<!ELEMENT photo #PCDATA)>
Year declare as id.So we must follow id rule for the year attribute of model. Suppose u want...Leave a comment:
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hi,
Please ignore the previous mail.
here is ur xml
<?xml version="1.0" encoding="UTF-8"?>
<?xml-stylesheet type="text/xsl" href="group.xsl "?>
<group>
<categorylist >
<category>car </category>
<description>be ntly</description>
</categorylist>
<categorylist >...Leave a comment:
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hi,
here ouput is the clear. Please verify in ur xml and xsl coding.
<?xml version="1.0" encoding="UTF-8"?>
<?xml-stylesheet type="text/xsl" href="group.xsl "?>
<group>
<categorylist >
<category>car </category>
<description>be ntly</description>
</categorylist>
<categorylist >...Leave a comment:
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hi declare the variable for category and description
like this
<xsl:key name="keyCatego ry" match="category list" use="category"/>
<xsl:key name="keyDescri ption" match="category list" use="descriptio n"/>
and apply ur xslt coding like these
<xsl:for-each select="$group" >
<xsl:variable...Leave a comment:
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hi,
Use acrobat professional save as type: xml 1.0(*.xml)
U select the file menu
file>saves as>.xmlLeave a comment:
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hi,
I can't get ur qusetion. Please resend ur queries briefly & clearly with expect output.Leave a comment:
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perl xpath based
Hi all
I have doubt in perl script within XML.
This is XML data:
[CODE=xml]<float id="1" type="box"><flo at id="2" type="need"><float id="3" type="new">Alth ough there are a number of commercial sites that have free legal information, FindLaw (<uri km="Bm.Ap.A_1.A _URL.A.URL" xlink:href="htt p://www.findlaw.com ">www.findlaw.c om</uri>)</float></float><float... -
Hi,
I got the result for this. Please ignore it.
Any way solution is
<xsl:value-of select="sum($re port[date=$date][user=$user]/totaltime)"/>
QUOTE=saran3b2]Hi all,
Please suggest us.
My xml file is
<?xml version="1.0" encoding="UTF-8"?>
<?xml-stylesheet type="text/xsl" href="Y:\02-Thomson\Users\A PT\xsl\vinoth-new.xsl"?>...Leave a comment:
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Sum of the time base by date
Hi all,
Please suggest us.
My xml file is
<?xml version="1.0" encoding="UTF-8"?>
<?xml-stylesheet type="text/xsl" href="Y:\02-Thomson\Users\A PT\xsl\vinoth-new.xsl"?>
<report>
<production>
<dept></dept>
<etype>Break</etype>
<user>thiyagu </user>
<date>2/5/2008</date>... -
hi,
please ignore that watch the my reply to MarkoKlacar for clear doubt...Leave a comment:
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Hi MarkoKlacar,
Thanks 4 ur reply. As per previous mail. I have the (etype, user, book, file, status, task, starttime, endtime, totaltime, updateto, comment) elements. Here i want display these elements in stylesheet by
Date wise then task wise (All are must be ascending order in sub sorting) then user wise like as below mentioned:
Date: 2/5/2008
Task: RND
User: Thiyagu...Leave a comment:
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Sorting the element with in the sorting element
Hi all,
If u know the solution please suggest me. I need these urgent.
production.xml
[code=xml]
<?xml version="1.0" encoding="UTF-8"?>
<?xml-stylesheet type="text/xsl" href="xsl/vinoth-new.xsl"?>
<report>
<production>
<etype>Break</etype>
<user>thiyagu </user>
<date>3/5/2008</date>... -
hi Mohd Baseerul Mubeen
sorry for wrong mail. i am new user
so i have checked...Leave a comment:
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variable in xslt
hi friends
i am new user.
i am in the process of collecting the main content and number of title from the input XML with XSLT.
I have doubt in variable increament. how to increamtent variable ?
this is my xml:
...Code:<chunk-meta><title km="Pt.Ttl">PT</title></chunk-meta> <chunk-meta><title km="At.Ttl">no need</title></chunk-meta>
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variable in xslt
hi friends
i am new user.
i am in the process of collecting the main content and number of title from the input XML with XSLT.
I have doubt in variable increament. how to increamtent variable ?
this is my xml:
...Code:<chunk-meta><title km="Pt.Ttl">PT</title></chunk-meta> <chunk-meta><title km="At.Ttl">no need</title></chunk-meta>
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