How to Fetch the node using stylesheet

[amollokhande1]

Hi All,

I am having xml in following format

<Form>

<Panel id="1" name="t1">
    <Field1/>
   <Field2/>
</Panel>

<Panel id="2" name="t2">
    <Field1/>
   <Field2/>
</Panel>

</Form>

Now my requirement is to fetch the Panel node with id="2" by using xslt for further processing for component.

Can anybody let me know how to fetch the node using XSLT?

Regards
Amol Lokhande

[Dormilich]

XPath will get you the node.

[amollokhande1]

Hi,

I have written following xslt but it is not returning me the required output

<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:msxsl="urn:schemas-microsoft-com:xslt" version="1.0">
	
<xsl:template match="/">
	<xsl:call-template name ="GetPanelNode">
	</xsl:call-template>
</xsl:template>

<xsl:template name="GetPanelNode" match="*">
	Test
	 <xsl:value-of select="//Form/Data/Panel[@id='2']/node()"/>
	 Test
</xsl:template>
</xsl:stylesheet>

Regards
Amol Lokhande

[Dormilich]

there's no such element as <Data> present in your XML

further, there are no visible data in your XML, so you can't see (even if you successfully selected) the node

[amollokhande1]

Sorry that was typo mistake

<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:msxsl="urn:schemas-microsoft-com:xslt" version="1.0">
  
<xsl:template match="/">
    <xsl:call-template name ="GetPanelNode">
     </xsl:call-template>
 </xsl:template>
  
<xsl:template name="GetPanelNode" match="*">
<xsl:value-of select="//Form/Panel[@id='2']/node()"/>

 </xsl:template>
</xsl:stylesheet>

[Dormilich]

see the edited comment above

further, please use [code] tags when posting code, makes it easier to read.

[amollokhande1]

Ok, here is the stylesheet

<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:msxsl="urn:schemas-microsoft-com:xslt" version="1.0">
  
<xsl:template match="/">
<xsl:call-template name ="GetPanelNode">
</xsl:call-template>
</xsl:template>
  
<xsl:template name="GetPanelNode" match="*">
      <xsl:value-of select="//Form/Panel[@id='2']/node()"/>
  </xsl:template>
 </xsl:stylesheet>

[Dormilich]

your main problem is, that you don't have any visual output.

[amollokhande1]

Hi,

I am not getting you. I am testing this stylesheet againt the xml using the transformation in Vb application which is not returning any xml data

Regards
Amol Lokhande

[Dormilich]

XSLT is used to transfer one XML into another (or text), so XSLT's return value is a string. the string contains everyting that XSLT "would print" to the screen.

if you don't "write" anything there will only be an empty return.

in your example the only output can come from the <Panel> nodes, but because they contain no text, thus no output and no return string.

[jkmyoung]

Are you trying to copy the entire node? You might want to use copy-of instead of value-of.

<xsl:copy-of select="//Form/Panel[@id='2']"/>

[amollokhande1]

Thanks a lot. It worked