for-each IDREF

[Dormilich]

Hello,

I'm back with a problem, where I need help with starting.
I got an XML file that contains a number of elements with IDREF type attributes:

<?xml version="1.0" ?>
<root>
// these elements contain all the info for the groups
// name is of type ID
  <group name="group1" … />
  <group name="group2" … />
  <group name="group3" … />
  <collection>
// group is of type IDREF
// there can be any number of elements
    <item group="group1">…</item>
    <item group="group1">…</item>
    <item group="group2">…</item>
  <collection>
<root>

in XSL I want to loop over each group of <item> inside the <collection> (ideally using the idref() function) but I do not know all the values of the IDREF attribute (this number may change over time/file/element). Is there any way to get these values?

// desired result
<div id="group1">
  <a … >
  <a … >
</div>
<div id="group2">
  <a … >
</div>

I know that I could loop over all elements (using <xsl:sort>) and check if the attribute value is still the same. Is there a more elegant way? (something like getting the IDREF attribute values first and then call it by idref() (or @group))

Is it possible to somehow get all the ID values of <group> and iterate over each of them?

thanks

PS: once I know all the IDREFS inside <collection> there are no problems I can foresee

[jkmyoung]

Do you mean this? If not, what more are you looking for; what do you mean by idref? Is this a processor specific function, eg Xalan?

[code=xml]
<xsl:template match="group">
<div id="{@name}">
<xsl:apply-templates select="//collection/item[@group = current()/@name]"/>
</div>
</xsl:template>
[/code]

[Dormilich]

what do you mean by idref? Is this a processor specific function, eg Xalan?

I mean this:

<!ELEMENT item ...>
<!ATTLIST item 
    group    IDREF    #IMPLIED
    ... >

I'll dive into the code tomorrow...

regards

PS: XML Schema also know ID/IDREF type attribute definitions

[Dormilich]

currently I'm looking into muenchian grouping. will post back if I can see some light....

[Dormilich]

solved it using Muenchian Grouping (pretty much the thing I needed).
files (too long to post):
XML (gives YSOD in FF)
XSL
DTD