<need help>How to print the preceding elem value based on descendant node in XSLT?

[njsimha]

Hi,
In the folowing XML snippet:

<template1>
<name>student</name>
<elem1>
<[B]subelem1[/B]>65</[B]subelem1[/B]>
<subelem2>15</subelem2>
</elem1>
<[B]elem2[/B]>100</[B]elem2[/B]>
</template1>

</root>

For the above code,I need to display an error:
"elem2 node is not allowed for name=student as subelem1 is greater than 50"

so the requirement is,elem2 should not be present if subelem1 is > 50.

I have the following XSLT code:

<xsl:template match="/root/template1/elem1/subelem1">
<xsl:variable name="value" select="." />
<xsl:if test="$value > 50" >
subelem1 is greater than 50
<xsl:if test="../../elem2" >
<xsl:message terminate="yes" >
<xsl:value-of select="concat( "elem2 is not allowed for name=....")/>
elem4 exists
</xsl:if>
</xsl:if>
</xsl:template>

Using the above code,I am able to print the error as "elem2 is not allowed for name= ".
Here I am not able to print "name=student". How to print the value of name node?

Also please note that there will be 10 <template1> nodes.so the XSLT has to work for each template1.

Please reply me how to achieve this.

Thanks,

[jkmyoung]

1. Since you need it to run for every template1 node, I suggest you change the template to match template1.
2. Use paths relative to template1 node. Note change in variable value.

[code=xml]
<xsl:template match="template 1">
<xsl:variable name="value" select="elem1/subelem1"/>
<xsl:if test="$value &gt; 50">
subelem1 is greater than 50
<xsl:if test="elem2">
<xsl:message terminate="yes"/>
<xsl:value-of select="concat( 'elem2 is not allowed for name=', name)"/>
elem4 exists
</xsl:if>
</xsl:if>
<xsl:template >
[/code]

[njsimha]

Hi young,
Thanks for your reply but I am sorry that it didnt work.what else can be changed to this?

Thanks,

1. Since you need it to run for every template1 node, I suggest you change the template to match template1.
2. Use paths relative to template1 node. Note change in variable value.

[code=xml]
<xsl:template match="template 1">
<xsl:variable name="value" select="elem1/subelem1"/>
<xsl:if test="$value &gt; 50">
subelem1 is greater than 50
<xsl:if test="elem2">
<xsl:message terminate="yes"/>
<xsl:value-of select="concat( 'elem2 is not allowed for name=', name)"/>
elem4 exists
</xsl:if>
</xsl:if>
<xsl:template >
[/code]

[jkmyoung]

If you need to use the same template (subelem1) you can use <xsl:for-each ..\.. to change context to the template1 node:
[code=xml]
<xsl:template match="/root/template1/elem1/subelem1">
<xsl:for-each select="..\..">
all previous code
[/code]

[njsimha]

Hi young,
Its working now.Thanks a lot.

If you need to use the same template (subelem1) you can use <xsl:for-each ..\.. to change context to the template1 node:
[code=xml]
<xsl:template match="/root/template1/elem1/subelem1">
<xsl:for-each select="..\..">
all previous code
[/code]

[Dormilich]

I would have gone for:

<xsl:template match="//template1">
  <xsl:if test=".[elem2][elem1/subelem1 &amp;gt; 50]">
... error message here ...
  </xsl:if>
</xsl:template>

regards