Find Xpath Expn of current node using ancestor-or-self

[Muthu08]

I'm trying to Xpath EXprn for a current node(name unknown).I tried using the below syntax,but it fails .Pls help.



<xsl:variable name= "xpath" select ="name(ances tor-or-self::(.))"/>

[jkmyoung]

probably
<xsl:variable name="xpath" select="name()"/>
or
<xsl:variable name="xpath" select="local-name()"/>

[Muthu08]

nmae() or local-name() would only return me th ename of the current node.But i'm trying to find out the Xpath Expression ,which would return the ancestors names also

I need the name of current node plus its ancestors.

ex: root/toplevelnode1/node2/ current node

So i tried :

<xsl:variable name= "xpath" select ="name(ances tor-or-self::[name()])"/>

I need the syntax which would return current nodes path from the root.Pls help.

thanks in advance.

[jkmyoung]

[code=xml]<xsl:variable name= "xpath">
<xsl:for-each select="ancesto r::*">
<xsl:value-of select="name()"/><xsl:text>/</xsl:text>
</xsl:for-each>
<xsl:value-of select="name()"/>
</xsl:variable>[/code]

[Muthu08]

Cool!! That worked Thanks!!