Display XML nodes whose parent node has a certain attribute (or attribute value)

[npm]

I'm trying to display XML nodes whose parent node has a certain attribute (or attribute value). I have one code that works in Firefox, but not IE and another code that works in IE, but not Firefox.

This one works in FF, but not IE:

<script type="text/javascript">
xmlDoc=loadXMLD oc("sampleFileZ .xml");
x=xmlDoc.getEle mentsByTagName( "sampleNode ");
for (i=0;i<x.length ;i++)
{
if (x[i].parentNode.has Attribute("samp leAtt"))
{
document.write( x[i].childNodes[0].nodeValue)
document.write( "<br />")
}
}
</script>

---------------------------------------

This one works in IE, but not FF:

<script language="JavaS cript" type="text/javascript">
xmlDoc=loadXMLD oc("sampleFile. xml");
xmlDoc.setPrope rty("SelectionL anguage", "XPath");
x=xmlDoc.select Nodes("//node1[@att='value']/node2");
for (i=0;i<x.length ;i++)
{
document.write( x[i].childNodes[0].nodeValue)
document.write( "<br />")
}
</script>

Is there one javascript (maybe one like the first one that uses an if statement) that will work in both browsers?

Thanks so much!

[drhowarddrfine]

Probably not the problem but this is not valid:
<script language="JavaS cript" type="text/javascript">

Change it to:
<script type="text/javascript">

[npm]

Thanks! I changed it.

Does anyone have a suggestion on how to work this out?