how can I use two txtbox to enter aphanumeric value and change it

[cipher2079]

how can I use two txtbox to enter aphanumeric value and taking the first value of the textbox and placing it in the second txtbox with the numbers value being change to the actual wording (1,2 changes to one, two).

[willakawill]

how can I use two txtbox to enter aphanumeric value and taking the first value of the textbox and placing it in the second txtbox with the numbers value being change to the actual wording (1,2 changes to one, two).

Hi. What limits did you have in mind for these numbers?
For instance, do you want to have "one million five hundred thousand and forty two"

[cipher2079]

Hi. What limits did you have in mind for these numbers?
For instance, do you want to have "one million five hundred thousand and forty two"

up to 10 is fine

[cipher2079]

up to 10 is fine

can someone please help me I having such a hard time.

[willakawill]

can someone please help me I having such a hard time.

You can do it this way using an array and the Split() function

This works though there are no checks on the user input

    Dim stAr(10) As String
    Dim arInput As Variant
    Dim stOutput As String
    Dim intLoop As Integer
    
    stAr(0) = "zero"
    stAr(1) = "one"
    stAr(2) = "two"
    stAr(3) = "three"
    stAr(4) = "four"
    stAr(5) = "five"
    stAr(6) = "six"
    stAr(7) = "seven"
    stAr(8) = "eight"
    stAr(9) = "nine"
    stAr(10) = "ten"
    
    arInput = Split(Me.txtInput.Text, ",")
    For intLoop = 0 To UBound(arInput) - 1
        stOutput = stOutput & stAr(CInt(arInput(intLoop))) & ", "
    Next intLoop
    stOutput = stOutput & stAr(CInt(arInput(intLoop)))
    Me.txtOutput.Text = stOutput

[cipher2079]

You can do it this way using an array and the Split() function

This works though there are no checks on the user input

    Dim stAr(10) As String
    Dim arInput As Variant
    Dim stOutput As String
    Dim intLoop As Integer
    
    stAr(0) = "zero"
    stAr(1) = "one"
    stAr(2) = "two"
    stAr(3) = "three"
    stAr(4) = "four"
    stAr(5) = "five"
    stAr(6) = "six"
    stAr(7) = "seven"
    stAr(8) = "eight"
    stAr(9) = "nine"
    stAr(10) = "ten"
    
    arInput = Split(Me.txtInput.Text, ",")
    For intLoop = 0 To UBound(arInput) - 1
        stOutput = stOutput & stAr(CInt(arInput(intLoop))) & ", "
    Next intLoop
    stOutput = stOutput & stAr(CInt(arInput(intLoop)))
    Me.txtOutput.Text = stOutput

Thanks but can I actually use this with vb
I am actually trying to run it in VB 2005 express edition

[cipher2079]

Thanks but can I actually use this with vb
I am actually trying to run it in VB 2005 express edition

I really appreciate your help

Thanks again

[willakawill]

Thanks but can I actually use this with vb
I am actually trying to run it in VB 2005 express edition

I have no idea if this runs on .NET or not. Why not test it and see.
Put a couple of textboxes on a form with a button and paste this code into the button_click event. I tested the code with VB6

Let us know if it works.
Good luck

[cipher2079]

I have no idea if this runs on .NET or not. Why not test it and see.
Put a couple of textboxes on a form with a button and paste this code into the button_click event. I tested the code with VB6

Let us know if it works.
Good luck

Thanks for your reply,

everything seems to be fine however, I get an error "variable 'stOutput' is used before it has been assigned a value. A null refference exception could result at runtime" and is this vb coding? I think it is.

[willakawill]

Thanks for your reply,

everything seems to be fine however, I get an error "variable 'stOutput' is used before it has been assigned a value. A null refference exception could result at runtime" and is this vb coding? I think it is.

Try this just after the last Dim statement
stOutput = ""

[cipher2079]

Try this just after the last Dim statement
stOutput = ""

Now I get A different error for this line stOutput = stOutput & stAr(CInt(arInp ut(intLoop)))

error: Conversion from string "jkhkjh" to type 'Integer' is not valid.

sorry about the stupid question. Yeah it is vb

[cipher2079]

Try this just after the last Dim statement
stOutput = ""

Now I get a different error for this line stOutput = stOutput & stAr(CInt(arInp ut(intLoop)))

error: Conversion from string "juji67" to type 'Integer' is not valid.

[cipher2079]

Now I get a different error for this line stOutput = stOutput & stAr(CInt(arInp ut(intLoop)))

error: Conversion from string "juji67" to type 'Integer' is not valid.

oh this is page two I was looking for the last post I thought it was on page 1

[willakawill]

oh this is page two I was looking for the last post I thought it was on page 1

Did you copy and paste this code or did you type it in.
There is no error when run under vb6
What is being typed into the first textbox. this should be numbers separated by a comma.

[willakawill]

Now I get A different error for this line stOutput = stOutput & stAr(CInt(arInp ut(intLoop)))

error: Conversion from string "jkhkjh" to type 'Integer' is not valid.

sorry about the stupid question. Yeah it is vb

This includes a check for numeric entries

    Dim stAr(10) As String
    Dim arInput As Variant
    Dim stOutput As String
    Dim intLoop As Integer
    
    stOutput = ""

    stAr(0) = "zero"
    stAr(1) = "one"
    stAr(2) = "two"
    stAr(3) = "three"
    stAr(4) = "four"
    stAr(5) = "five"
    stAr(6) = "six"
    stAr(7) = "seven"
    stAr(8) = "eight"
    stAr(9) = "nine"
    stAr(10) = "ten"
    
    arInput = Split(Me.txtInput.Text, ",")
    For intLoop = 0 To UBound(arInput) - 1
        If IsNumeric(arInput(intLoop) Then
            stOutput = stOutput & stAr(CInt(arInput(intLoop))) & ", "
        Else
            MsgBox "Please enter single numbers separated by a comma"
            Me.txtInput.Text = ""
            Me.txtInput.SetFocus
            Exit Sub
        End If
    Next intLoop
    stOutput = stOutput & stAr(CInt(arInput(intLoop)))
    Me.txtOutput.Text = stOutput