need a reg expression

[AAaron123]

I want to search my .vb files for lines that do not contain an underline
followed by Menu.

I tried [!_].*Menu as a regular expression but I guess that must mean that
it must contain a character that is not an _ followed by Menu.

Is that correct?

what would work?

thanks

[jamil@onepost.net]

Re: need a reg expression

On Wed, 9 Apr 2008 07:38:24 -0400, "AAaron123"
<aaaron123@road runner.comwrote :

>Thanks that's good to know.
>
>I'm thinking now that
>[!_].*Menu
>means to find a character other than _ followed by Menu.
>
>I need to find a line that has no _ at all, followed by Menu.
>
>Thanks again

If you mean the _ character immediately followed by Menu (no spacing),
try this:

(?<!_)(?:Menu|)

Test subjects:

123 _Menu 566
123 Menu 456
123 456
123_ Menu 456

Lines two and four match. The rest do not.

If you mean the _ character followed by Menu (including spacing), try
this:

(?<!_\s*)(?:Men u|)

Line two matches the test subjects. The rest do not.

[jamil@onepost.net]

Re: need a reg expression

On Thu, 10 Apr 2008 06:33:25 -0400, jamil@onepost.n et wrote:

>If you mean the _ character immediately followed by Menu (no spacing),
>try this:
>
>(?<!_)(?:Menu| )

You can simplify this and get the same result by removing the last
group:

(?<!_)Menu

I created this quickly this morning and forgot to remove it.

>If you mean the _ character followed by Menu (including spacing), try
>this:
>
>(?<!_\s*)(?:Me nu|)

Same for this one:

(?<!_\s*)Menu

[AAaron123]

Re: need a reg expression

What I meant is that the word Menu should appear and that there should not
be an underscore any place before it.

Are you using ! for negation? Shouldn't it be ^ (see Tom Shelton's earlier
reply.)

Thanks a lot


<jamil@onepost. netwrote in message
news:dc5tv3l92o etsqmdb4mvemlqp hv27n26q1@4ax.c om...

On Thu, 10 Apr 2008 06:33:25 -0400, jamil@onepost.n et wrote:
>

>>If you mean the _ character immediately followed by Menu (no spacing),
>>try this:
>>
>>(?<!_)(?:Menu |)

>
You can simplify this and get the same result by removing the last
group:
>
(?<!_)Menu
>
I created this quickly this morning and forgot to remove it.
>

>>If you mean the _ character followed by Menu (including spacing), try
>>this:
>>
>>(?<!_\s*)(?:M enu|)

>
Same for this one:
>
(?<!_\s*)Menu

[jamil@onepost.net]

Re: need a reg expression

On Fri, 11 Apr 2008 15:16:11 -0400, "AAaron123"
<aaaron123@road runner.comwrote :

>What I meant is that the word Menu should appear and that there should not
>be an underscore any place before it.

Then try this:

(?<!_.*)Menu

>Are you using ! for negation? Shouldn't it be ^ (see Tom Shelton's earlier
>reply.)
>
>Thanks a lot

The earlier reply doesn't do what you are asking for.

[jamil@onepost.net]

Re: need a reg expression

On Fri, 11 Apr 2008 15:16:11 -0400, "AAaron123"
<aaaron123@road runner.comwrote :

>What I meant is that the word Menu should appear and that there should not
>be an underscore any place before it.

Then try this:

(?<!_.*)Menu

>Are you using ! for negation? Shouldn't it be ^ (see Tom Shelton's earlier
>reply.)
>
>Thanks a lot

The earlier reply doesn't do what you are asking for.

[AAaron123]

Re: need a reg expression

That works.

Are Regular expressions rules the same in, say, Unix, Perl and Windows?


Thanks

And I found out about [^aeiou] and (?<! ) so thanks to Tom Shelton also


<jamil@onepost. netwrote in message
news:je00049nor blelu4mvsmj9brm s6nuurge0@4ax.c om...

On Fri, 11 Apr 2008 15:16:11 -0400, "AAaron123"
<aaaron123@road runner.comwrote :
>

>>What I meant is that the word Menu should appear and that there should not
>>be an underscore any place before it.

>
Then try this:
>
(?<!_.*)Menu
>

>>Are you using ! for negation? Shouldn't it be ^ (see Tom Shelton's
>>earlier
>>reply.)
>>
>>Thanks a lot

>
The earlier reply doesn't do what you are asking for.

[AAaron123]

Re: need a reg expression

I'm using Regex.Match and (?<!_.*)Menu works OK if there is just one line
but if I give it the following string it does not match the second line.

fhgfghfh_dfdfg

sdfsdfsdfMenu

sdfsdfsdf

Do I have to call it one line at a time?



Thanks again



I tried with out success: with and without RegexOptions.Mu ltiline.

Also tried with out success: ^(?<!_.*)Menu

Not really sure what these constructs mean, just trying things.








<jamil@onepost. netwrote in message
news:je00049nor blelu4mvsmj9brm s6nuurge0@4ax.c om...

On Fri, 11 Apr 2008 15:16:11 -0400, "AAaron123"
<aaaron123@road runner.comwrote :
>

>>What I meant is that the word Menu should appear and that there should not
>>be an underscore any place before it.

>
Then try this:
>
(?<!_.*)Menu
>

>>Are you using ! for negation? Shouldn't it be ^ (see Tom Shelton's
>>earlier
>>reply.)
>>
>>Thanks a lot

>
The earlier reply doesn't do what you are asking for.

[jamil@onepost.net]

Re: need a reg expression

On Sat, 12 Apr 2008 03:33:34 -0400, "AAaron123"
<aaaron123@road runner.comwrote :

>That works.
>
>Are Regular expressions rules the same in, say, Unix, Perl and Windows?
>
>
>Thanks

Different regular expressions engines exhibit different behavior and
features. They all share similarities though.

The engine in .NET is quite powerful and full-featured.

[jamil@onepost.net]

Re: need a reg expression

On Sat, 12 Apr 2008 04:02:29 -0400, "AAaron123"
<aaaron123@road runner.comwrote :

>I'm using Regex.Match and (?<!_.*)Menu works OK if there is just one line
>but if I give it the following string it does not match the second line.
>
>fhgfghfh_dfd fg
>
>sdfsdfsdfMen u
>
>sdfsdfsdf
>
>Do I have to call it one line at a time?

I just threw together some quick code that works fine:

Dim oRegex As Regex
Dim oMatch As Match
Dim strTest As String

strTest = "fhgfghfh_dfdfg " & vbCrLf & "sdfsdfsdfM enu" & vbCrLf &
"sdfsdfsdf"

oRegex = New Regex("(?<!_.*) Menu")
oMatch = oRegex.Match(st rTest)

While oMatch.Success
Call MsgBox("Matched at position: " & oMatch.Index,
MsgBoxStyle.Inf ormation)
oMatch = oMatch.NextMatc h
End While

Call MsgBox("No more matches found.", MsgBoxStyle.Inf ormation)

[AAaron123]

Re: need a reg expression

Thanks for all the help.
Besides what you showed me my underlying problem was the string contained
CR(13) for line endings.
I checked a RichTextBox.Tex t and it contained LF for line endings.
I expected CRLF since I thought the was the way of Windows.

Any way I replace CR wit LF and replace works OK now.

Must be Regex looks for LF.
Sound right to you?

I'd like my code to act the same as
VS2008/Edit/Find In Files/Use Regular Expressions

Do you know or can you surmise if it uses any of the following?
Take a guess otherwise - it would be a better guess than mine.


The RegexOptions Enumeration contains:

Multiline
ExplicitCapture
Singleline
IgnorePatternWh itespace
ECMAScript
CultureInvarian t

Thanks again

[jamil@onepost.net]

Re: need a reg expression

On Sun, 13 Apr 2008 09:55:06 -0400, "AAaron123"
<aaaron123@road runner.comwrote :

>Thanks for all the help.

No problem.

>Besides what you showed me my underlying problem was the string contained
>CR(13) for line endings.
>I checked a RichTextBox.Tex t and it contained LF for line endings.
>I expected CRLF since I thought the was the way of Windows.
>
>Any way I replace CR wit LF and replace works OK now.
>
>Must be Regex looks for LF.
>Sound right to you?

In UNIX, yes. A line termination is a LF. In Windows typically, no. A
line termination is typically a carriage return and linefeed
combination. I've not tested this under .NET's engine, but it could be
using UNIX style line terminations.

>I'd like my code to act the same as
>VS2008/Edit/Find In Files/Use Regular Expressions
>
>Do you know or can you surmise if it uses any of the following?
>Take a guess otherwise - it would be a better guess than mine.

I do not yet own VS2008 (I saw no good reason to upgrade from 2005).
I'm not sure if this particular sample was included with VS2005,
because I have no samples installed.

If you could give a summary of what it is you're trying to accomplish,
or perhaps someone else could help out on this question.

[AAaron123]

Re: need a reg expression


<jamil@onepost. netwrote in message
news:k59604tt3k hthan2vls5b8voh 6toei5ae7@4ax.c om...

On Sun, 13 Apr 2008 09:55:06 -0400, "AAaron123"
<aaaron123@road runner.comwrote :
>

>>Thanks for all the help.

>
No problem.
>

>>Besides what you showed me my underlying problem was the string contained
>>CR(13) for line endings.
>>I checked a RichTextBox.Tex t and it contained LF for line endings.
>>I expected CRLF since I thought the was the way of Windows.
>>
>>Any way I replace CR wit LF and replace works OK now.
>>
>>Must be Regex looks for LF.
>>Sound right to you?

>
In UNIX, yes. A line termination is a LF. In Windows typically, no. A
line termination is typically a carriage return and linefeed
combination. I've not tested this under .NET's engine, but it could be
using UNIX style line terminations.
>

>>I'd like my code to act the same as
>>VS2008/Edit/Find In Files/Use Regular Expressions
>>
>>Do you know or can you surmise if it uses any of the following?
>>Take a guess otherwise - it would be a better guess than mine.

>
I do not yet own VS2008 (I saw no good reason to upgrade from 2005).
I'm not sure if this particular sample was included with VS2005,
because I have no samples installed.
>
If you could give a summary of what it is you're trying to accomplish,
or perhaps someone else could help out on this question.

No need.
You solve my problem.
Mostly just curious now.
Thanks