Variable isn't decalred error --but it is!

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  • Jerry West
    #1

    Variable isn't decalred error --but it is!

    I have a 'variable not declared' error occurring when in fact the var is
    declared --its just nested in a If Then statement. Like so:

    If bPortrait Then

    'then its in portrait mode

    ' Make a bitmap for the result.
    Dim bm_dest As New Bitmap(CInt(bm_ source.Height *
    scale_factor), CInt(bm_source. Width * scale_factor))

    Else

    'then it's in landscape mode

    ' Make a bitmap for the result.
    Dim bm_dest As New Bitmap(CInt(bm_ source.Width *
    scale_factor), CInt(bm_source. Height * scale_factor))

    End If

    Why do I get this error when either way the If Then clause falls the var is
    declared and will execute? I understand that I can set the If Then clause
    for the height & width values and then declare the var outside of that. But
    why doesn't the above --which is functionally equivalent-- work?

    JW


    Tags: None
    • =?Utf-8?B?S2VycnkgTW9vcm1hbg==?=
      #2
      RE: Variable isn't decalred error --but it is!

      JW,

      Where do you get the error?

      Kerry Moorman


      "Jerry West" wrote:
      I have a 'variable not declared' error occurring when in fact the var is
      declared --its just nested in a If Then statement. Like so:
      >
      If bPortrait Then
      >
      'then its in portrait mode
      >
      ' Make a bitmap for the result.
      Dim bm_dest As New Bitmap(CInt(bm_ source.Height *
      scale_factor), CInt(bm_source. Width * scale_factor))
      >
      Else
      >
      'then it's in landscape mode
      >
      ' Make a bitmap for the result.
      Dim bm_dest As New Bitmap(CInt(bm_ source.Width *
      scale_factor), CInt(bm_source. Height * scale_factor))
      >
      End If
      >
      Why do I get this error when either way the If Then clause falls the var is
      declared and will execute? I understand that I can set the If Then clause
      for the height & width values and then declare the var outside of that. But
      why doesn't the above --which is functionally equivalent-- work?
      >
      JW
      >
      >
      >

        Comment

        • Jerry West
          #3
          Re: Variable isn't decalred error --but it is!

          You mean when do I encounter the error? If so, the code window underlines
          every instance of bm_dest; flagging it as an error. As well, if I try to run
          the code I am not allowed to. Is that what you mean?

          JW

          "Kerry Moorman" <KerryMoorman@d iscussions.micr osoft.comwrote in message
          news:57710FC2-7472-4940-A17B-948C8803CBF8@mi crosoft.com...
          JW,
          >
          Where do you get the error?
          >
          Kerry Moorman
          >
          >
          "Jerry West" wrote:
          >
          >I have a 'variable not declared' error occurring when in fact the var is
          >declared --its just nested in a If Then statement. Like so:
          >>
          > If bPortrait Then
          >>
          > 'then its in portrait mode
          >>
          > ' Make a bitmap for the result.
          > Dim bm_dest As New Bitmap(CInt(bm_ source.Height *
          >scale_factor ), CInt(bm_source. Width * scale_factor))
          >>
          > Else
          >>
          > 'then it's in landscape mode
          >>
          > ' Make a bitmap for the result.
          > Dim bm_dest As New Bitmap(CInt(bm_ source.Width *
          >scale_factor ), CInt(bm_source. Height * scale_factor))
          >>
          > End If
          >>
          >Why do I get this error when either way the If Then clause falls the var
          >is
          >declared and will execute? I understand that I can set the If Then clause
          >for the height & width values and then declare the var outside of that.
          >But
          >why doesn't the above --which is functionally equivalent-- work?
          >>
          >JW
          >>
          >>
          >>

            Comment

            • =?Utf-8?B?S2VycnkgTW9vcm1hbg==?=
              #4
              Re: Variable isn't decalred error --but it is!

              JW,

              What I meant was are you trying to use the variable outside the If - Then -
              Else statement?

              If so, then that is your problem. The scope of the variable is only within
              the If - Then - Else statement. You need to dimension bm_dest at the top of
              the procedure:

              Dim bm_dest As BitMap

              and then set it to a new instance inside the If statement.

              Kerry Moorman


              "Jerry West" wrote:
              You mean when do I encounter the error? If so, the code window underlines
              every instance of bm_dest; flagging it as an error. As well, if I try to run
              the code I am not allowed to. Is that what you mean?
              >
              JW
              >
              "Kerry Moorman" <KerryMoorman@d iscussions.micr osoft.comwrote in message
              news:57710FC2-7472-4940-A17B-948C8803CBF8@mi crosoft.com...
              JW,

              Where do you get the error?

              Kerry Moorman


              "Jerry West" wrote:
              I have a 'variable not declared' error occurring when in fact the var is
              declared --its just nested in a If Then statement. Like so:
              >
              If bPortrait Then
              >
              'then its in portrait mode
              >
              ' Make a bitmap for the result.
              Dim bm_dest As New Bitmap(CInt(bm_ source.Height *
              scale_factor), CInt(bm_source. Width * scale_factor))
              >
              Else
              >
              'then it's in landscape mode
              >
              ' Make a bitmap for the result.
              Dim bm_dest As New Bitmap(CInt(bm_ source.Width *
              scale_factor), CInt(bm_source. Height * scale_factor))
              >
              End If
              >
              Why do I get this error when either way the If Then clause falls the var
              is
              declared and will execute? I understand that I can set the If Then clause
              for the height & width values and then declare the var outside of that.
              But
              why doesn't the above --which is functionally equivalent-- work?
              >
              JW
              >
              >
              >
              >
              >
              >

                Comment

                • Jerry West
                  #5
                  Re: Variable isn't decalred error --but it is!

                  Ah, got it. I didn't realize it's scope was relegated to only the If Then
                  statement. Thanks!

                  JW

                  "Kerry Moorman" <KerryMoorman@d iscussions.micr osoft.comwrote in message
                  news:F71C339A-074A-4D02-985C-FF8E3B745DED@mi crosoft.com...
                  JW,
                  >
                  What I meant was are you trying to use the variable outside the If -
                  Then -
                  Else statement?
                  >
                  If so, then that is your problem. The scope of the variable is only within
                  the If - Then - Else statement. You need to dimension bm_dest at the top
                  of
                  the procedure:
                  >
                  Dim bm_dest As BitMap
                  >
                  and then set it to a new instance inside the If statement.
                  >
                  Kerry Moorman
                  >
                  >
                  "Jerry West" wrote:
                  >
                  >You mean when do I encounter the error? If so, the code window underlines
                  >every instance of bm_dest; flagging it as an error. As well, if I try to
                  >run
                  >the code I am not allowed to. Is that what you mean?
                  >>
                  >JW
                  >>
                  >"Kerry Moorman" <KerryMoorman@d iscussions.micr osoft.comwrote in message
                  >news:57710FC 2-7472-4940-A17B-948C8803CBF8@mi crosoft.com...
                  JW,
                  >
                  Where do you get the error?
                  >
                  Kerry Moorman
                  >
                  >
                  "Jerry West" wrote:
                  >
                  >I have a 'variable not declared' error occurring when in fact the var
                  >is
                  >declared --its just nested in a If Then statement. Like so:
                  >>
                  > If bPortrait Then
                  >>
                  > 'then its in portrait mode
                  >>
                  > ' Make a bitmap for the result.
                  > Dim bm_dest As New Bitmap(CInt(bm_ source.Height *
                  >scale_factor ), CInt(bm_source. Width * scale_factor))
                  >>
                  > Else
                  >>
                  > 'then it's in landscape mode
                  >>
                  > ' Make a bitmap for the result.
                  > Dim bm_dest As New Bitmap(CInt(bm_ source.Width *
                  >scale_factor ), CInt(bm_source. Height * scale_factor))
                  >>
                  > End If
                  >>
                  >Why do I get this error when either way the If Then clause falls the
                  >var
                  >is
                  >declared and will execute? I understand that I can set the If Then
                  >clause
                  >for the height & width values and then declare the var outside of
                  >that.
                  >But
                  >why doesn't the above --which is functionally equivalent-- work?
                  >>
                  >JW
                  >>
                  >>
                  >>
                  >>
                  >>
                  >>

                    Comment

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