2005 error

[cj]

The below line gives me an error on DialogResult.No saying: "Access of
shared member, constant member, enum member or nested type through an
instance; qualifying expression will not be evaluated." It didn't give
me that in 2003. What does that mean?

If MessageBox.Show ("Copy from " & fromDir & " to " & toDir & " ?", "",
MessageBoxButto ns.YesNo, MessageBoxIcon. Question) = DialogResult.No Then

[Parag Joshi]

Re: 2005 error

HI CJ
Can you post the declarations for fromDir and toDir?
Regards
Parag

"cj" <cj@nospam.nosp amwrote in message
news:uz6flnSdHH A.3648@TK2MSFTN GP05.phx.gbl...

The below line gives me an error on DialogResult.No saying: "Access of
shared member, constant member, enum member or nested type through an
instance; qualifying expression will not be evaluated." It didn't give me
that in 2003. What does that mean?
>
If MessageBox.Show ("Copy from " & fromDir & " to " & toDir & " ?", "",
MessageBoxButto ns.YesNo, MessageBoxIcon. Question) = DialogResult.No Then

[=?Utf-8?B?S2VycnkgTW9vcm1hbg==?=]

RE: 2005 error

cj,

When you use DialogResult.No you are referencing the form's DialogResult
property, which is an instance of the DialogResult class.

Instead, use Windows.Forms.D ialogResult.No to access the shared member.

Kerry Moorman


"cj" wrote:

The below line gives me an error on DialogResult.No saying: "Access of
shared member, constant member, enum member or nested type through an
instance; qualifying expression will not be evaluated." It didn't give
me that in 2003. What does that mean?
>
If MessageBox.Show ("Copy from " & fromDir & " to " & toDir & " ?", "",
MessageBoxButto ns.YesNo, MessageBoxIcon. Question) = DialogResult.No Then
>

[ClayB]

Re: 2005 error

Instead of typing DialogResult.No , type the fully qualified Shared
property:

System.Windows. Forms.DialogRes ult.No

=============== ====
Clay Burch
Syncfusion, Inc.

[Herfried K. Wagner [MVP]]

Re: 2005 error

"cj" <cj@nospam.nosp amschrieb:

The below line gives me an error on DialogResult.No saying: "Access of
shared member, constant member, enum member or nested type through an
instance; qualifying expression will not be evaluated." It didn't give
me that in 2003. What does that mean?
>
If MessageBox.Show ("Copy from " & fromDir & " to " & toDir & " ?", "",
MessageBoxButto ns.YesNo, MessageBoxIcon. Question) = DialogResult.No Then

There is a name clash between the form's 'DialogResult' property and the
'DialogResult' type, and the compiler will bind to the property instead of
the type. To solve the problem, qualify the type name:

\\\
If d.ShowDialog() = System.Windows. Forms.DialogRes ult.OK Then
...
End If
///

--
M S Herfried K. Wagner
M V P <URL:http://dotnet.mvps.org/>
V B <URL:http://dotnet.mvps.org/dotnet/faqs/>

[Linda Liu [MSFT]]

RE: 2005 error

Hi Cj,

I performed a test based on your sample code but didn't reproduce the
problem on my side.

The namespace "System.Windows .Forms" is imported automatically in WinForms
application projects. In my test project, it's same whether I add the
namespace to the expression 'DialogResult.N o' (i.e.
System.Windows. Forms.DialogRes ult.No) or not.

But you may have a try adding the namespace to the 'DialogResult.N o' to see
if the problem still exists.

If the problem still exists, you may send me a sample project that could
just reproduce the problem. To get my actual email address, remove "online"
from my displayed email address.


Sincerely,
Linda Liu
Microsoft Online Community Support

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