IndexOf string method

[sh]

The IndexOf string method returns the position of the first occurrence
of a character in a string. Is there a method to find the x occurrence
of a character, for example, the 28th occurrence of a character in a string?

Thanks

[Cor Ligthert [MVP]]

Re: IndexOf string method

Shamanda,

I don't know if you are the same as gonzosez where is asked almost the same
question in the second message after yours.

\\\
dim mystring as string = "I contain 70 characters"
if mystring.length 27 then
dim TwentyEightchar = mystring(27)
end if
///
I hope this helps,

Cor

"sh" <shamada@prupip e.comschreef in bericht
news:PkmEg.6252 $Qf.139@newsrea d2.news.pas.ear thlink.net...

The IndexOf string method returns the position of the first occurrence of
a character in a string. Is there a method to find the x occurrence of a
character, for example, the 28th occurrence of a character in a string?
>
Thanks

[sh]

Re: IndexOf string method

Won't that give me what the 27th character is? I'm looking for the
position of the 27th occurrence of some character. For example

MyString = "12x34x56x78x90 x12x34x56x78x90 x"

So the position of the 7th occurrence of x is 21 (or 20 if zero based)

Cor Ligthert [MVP] wrote:

Shamanda,
>
I don't know if you are the same as gonzosez where is asked almost the same
question in the second message after yours.
>
\\\
dim mystring as string = "I contain 70 characters"
if mystring.length 27 then
dim TwentyEightchar = mystring(27)
end if
///
I hope this helps,
>
Cor
>
"sh" <shamada@prupip e.comschreef in bericht
news:PkmEg.6252 $Qf.139@newsrea d2.news.pas.ear thlink.net...
>

>>The IndexOf string method returns the position of the first occurrence of
>>a character in a string. Is there a method to find the x occurrence of a
>>character, for example, the 28th occurrence of a character in a string?
>>
>>Thanks

>
>
>

[Chris Dunaway]

Re: IndexOf string method

Cor Ligthert [MVP] wrote:

>
\\\
dim mystring as string = "I contain 70 characters"
if mystring.length 27 then
dim TwentyEightchar = mystring(27)
end if
///

Cor, you've missed what he wants to achieve. He wants to find the 28th
occurrence of a substring within a string.

One possible method (watch for typos):

Public Function FindNthOccurren ce(source As String, substring As
String, occurrence As Integer) As Integer
Dim index As Integer = -1
For i As Integer = 0 to occurrence - 1
index = source.IndexOf( substring, index + 1)
If index = -1 Then
Exit For
End If
Next

Return index
End Function

[Cor Ligthert [MVP]]

Re: IndexOf string method

Oh,

That is not to be done simple, you can use repeatly an indexof char, which
is many times quicker than a indexof from a string but you would have to
build code for that something as beneath not really tested see it as pseudo

\\\
dim mychar as char = "x"c
dim start as integer = 0
for x = 0 to 6
if start < mystring.lenth
start = mystring.indexo f(start, mychar)
else
exit for
end if
next
///

I hope this helps,

Cor

"sh" <shamada@prupip e.comschreef in bericht
news:HlnEg.8225 $xp2.2617@newsr ead1.news.pas.e arthlink.net...

Won't that give me what the 27th character is? I'm looking for the
position of the 27th occurrence of some character. For example
>
MyString = "12x34x56x78x90 x12x34x56x78x90 x"
>
So the position of the 7th occurrence of x is 21 (or 20 if zero based)
>
Cor Ligthert [MVP] wrote:

>Shamanda,
>>
>I don't know if you are the same as gonzosez where is asked almost the
>same question in the second message after yours.
>>
>\\\
>dim mystring as string = "I contain 70 characters"
>if mystring.length 27 then
>dim TwentyEightchar = mystring(27)
>end if
>///
>I hope this helps,
>>
>Cor
>>
>"sh" <shamada@prupip e.comschreef in bericht
>news:PkmEg.625 2$Qf.139@newsre ad2.news.pas.ea rthlink.net...
>>

>>>The IndexOf string method returns the position of the first occurrence of
>>>a character in a string. Is there a method to find the x occurrence of a
>>>character, for example, the 28th occurrence of a character in a string?
>>>
>>>Thanks

>>
>>