Waiting for process end , how?

[Bob]

Process.start(" Mydoc.doc") starts Word with the file. I need to wait for
Word to be closed before more code can execute in my app. How can I do this?

Thanks for any help
Bob

[Cor Ligthert [MVP]]

Re: Waiting for process end , how?

Bob,

How about to use the wait for exit in the process class to wait on the exit
of that process.

:-)

http://msdn2.microsoft.com/en-us/library/fb4aw7b8.aspx

I hope this helps,

Cor


"Bob" <bdufour@sgiims .comschreef in bericht
news:uSv4E59vGH A.3392@TK2MSFTN GP04.phx.gbl...

Process.start(" Mydoc.doc") starts Word with the file. I need to wait for
Word to be closed before more code can execute in my app. How can I do
this?
>
Thanks for any help
Bob
>

[Bob]

Re: Waiting for process end , how?

I been trying to do that with the following code
Dim pr As Process

pr.Start(Fname) where Fname is the filename to use with the process.

However I get a message in the IDE saying that Access of Shared member,
constant member.... etc. qualifying expression will not be evaluated.

Got any code snippets to do this? It seems straightforward but <GGGG:-)

Thanks for your help.

Bob



"Cor Ligthert [MVP]" <notmyfirstname @planet.nlwrote in message
news:ev8wQ89vGH A.4932@TK2MSFTN GP06.phx.gbl...

Bob,
>
How about to use the wait for exit in the process class to wait on the
exit of that process.
>
:-)
>

http://msdn2.microsoft.com/en-us/library/fb4aw7b8.aspx

>
I hope this helps,
>
Cor
>
>
"Bob" <bdufour@sgiims .comschreef in bericht
news:uSv4E59vGH A.3392@TK2MSFTN GP04.phx.gbl...

>Process.start( "Mydoc.doc" ) starts Word with the file. I need to wait for
>Word to be closed before more code can execute in my app. How can I do
>this?
>>
>Thanks for any help
>Bob
>>

>
>

[Tom Shelton]

Re: Waiting for process end , how?


Bob wrote:

I been trying to do that with the following code
Dim pr As Process
>
pr.Start(Fname) where Fname is the filename to use with the process.
>
However I get a message in the IDE saying that Access of Shared member,
constant member.... etc. qualifying expression will not be evaluated.
>
Got any code snippets to do this? It seems straightforward but <GGGG:-)
>
Thanks for your help.
>
Bob

Bob - here is a simple console application that demonstrates this
method:

Option Explicit On
Option Strict On

Imports System
Imports System.Diagnost ics

Module Module1

Public Sub Main()
Dim p As Process = Process.Start(" notepad.exe")
p.WaitForExit()
Console.WriteLi ne("Done")
End Sub

End Module


This is a blocking operation... Another way to do this, whithout
blocking would be:

Option Explicit On
Option Strict On

Imports System
Imports System.Threadin g
Imports System.Diagnost ics

Module Module1
Private WithEvents p As New Process
Private exited As Boolean = False

Public Sub Main()
p.EnableRaising Events = True
p.StartInfo.Fil eName = "notepad.ex e"
p.Start()

While Not exited
Thread.Sleep(10 00)
Console.WriteLi ne("Running!")
End While

Console.WriteLi ne("Done")
End Sub

Private Sub NotepadExited(B yVal sender As Object, ByVal e As
EventArgs) Handles p.Exited
exited = True
End Sub

End Module

Anwyay - HTH,

--
Tom Shelton [MVP]

[Cor Ligthert [MVP]]

Re: Waiting for process end , how?

Tom,

Exciting

:-)

Cor

"Tom Shelton" <tom@mtogden.co mschreef in bericht
news:1155659311 .605212.36440@7 4g2000cwt.googl egroups.com...

>
Bob wrote:

>I been trying to do that with the following code
>Dim pr As Process
>>
>pr.Start(Fname ) where Fname is the filename to use with the process.
>>
>However I get a message in the IDE saying that Access of Shared member,
>constant member.... etc. qualifying expression will not be evaluated.
>>
>Got any code snippets to do this? It seems straightforward but <GGGG:-)
>>
>Thanks for your help.
>>
>Bob

>
Bob - here is a simple console application that demonstrates this
method:
>
Option Explicit On
Option Strict On
>
Imports System
Imports System.Diagnost ics
>
Module Module1
>
Public Sub Main()
Dim p As Process = Process.Start(" notepad.exe")
p.WaitForExit()
Console.WriteLi ne("Done")
End Sub
>
End Module
>
>
This is a blocking operation... Another way to do this, whithout
blocking would be:
>
Option Explicit On
Option Strict On
>
Imports System
Imports System.Threadin g
Imports System.Diagnost ics
>
Module Module1
Private WithEvents p As New Process
Private exited As Boolean = False
>
Public Sub Main()
p.EnableRaising Events = True
p.StartInfo.Fil eName = "notepad.ex e"
p.Start()
>
While Not exited
Thread.Sleep(10 00)
Console.WriteLi ne("Running!")
End While
>
Console.WriteLi ne("Done")
End Sub
>
Private Sub NotepadExited(B yVal sender As Object, ByVal e As
EventArgs) Handles p.Exited
exited = True
End Sub
>
End Module
>
Anwyay - HTH,
>
--
Tom Shelton [MVP]
>

[Bob]

Re: Waiting for process end , how?

Thanks Tom Gonna give it a try.
Bob
"Tom Shelton" <tom@mtogden.co mwrote in message
news:1155659311 .605212.36440@7 4g2000cwt.googl egroups.com...

>
Bob wrote:

>I been trying to do that with the following code
>Dim pr As Process
>>
>pr.Start(Fname ) where Fname is the filename to use with the process.
>>
>However I get a message in the IDE saying that Access of Shared member,
>constant member.... etc. qualifying expression will not be evaluated.
>>
>Got any code snippets to do this? It seems straightforward but <GGGG:-)
>>
>Thanks for your help.
>>
>Bob

>
Bob - here is a simple console application that demonstrates this
method:
>
Option Explicit On
Option Strict On
>
Imports System
Imports System.Diagnost ics
>
Module Module1
>
Public Sub Main()
Dim p As Process = Process.Start(" notepad.exe")
p.WaitForExit()
Console.WriteLi ne("Done")
End Sub
>
End Module
>
>
This is a blocking operation... Another way to do this, whithout
blocking would be:
>
Option Explicit On
Option Strict On
>
Imports System
Imports System.Threadin g
Imports System.Diagnost ics
>
Module Module1
Private WithEvents p As New Process
Private exited As Boolean = False
>
Public Sub Main()
p.EnableRaising Events = True
p.StartInfo.Fil eName = "notepad.ex e"
p.Start()
>
While Not exited
Thread.Sleep(10 00)
Console.WriteLi ne("Running!")
End While
>
Console.WriteLi ne("Done")
End Sub
>
Private Sub NotepadExited(B yVal sender As Object, ByVal e As
EventArgs) Handles p.Exited
exited = True
End Sub
>
End Module
>
Anwyay - HTH,
>
--
Tom Shelton [MVP]
>

[Bob]

Re: Waiting for process end , how?

Thanks Tom,
Excellent info for me.
I've been testing the first snippet of code using Word instead of Notepad
Dim pr As Process = Process.Start(" Mydoc.doc") 'Starts Word and opens the
file OK
pr.WaitForExit( )
Console.WriteLi ne("Done")
However when execution hits the line p.WaitForExit() I get an unhandled
exception Object not set to an instance of an object. Normally this means
that I did not instantiate the pr object and indeed the code does not do
that (it would need the New keyword in he declaration) however with this
shared class you can not use the new keyword in the declaration.

How could I end up gettng Word to open up and have to wait before going back
to my application form that the process is closed. I look at the docs and I
see that Waitforexit does interrupt the calling thread and this is indeed
whats needed. I just don't see how to code it.

Any help is really, really appreciated.

Bob









"Tom Shelton" <tom@mtogden.co mwrote in message
news:1155659311 .605212.36440@7 4g2000cwt.googl egroups.com...

>
Bob wrote:

>I been trying to do that with the following code
>Dim pr As Process
>>
>pr.Start(Fname ) where Fname is the filename to use with the process.
>>
>However I get a message in the IDE saying that Access of Shared member,
>constant member.... etc. qualifying expression will not be evaluated.
>>
>Got any code snippets to do this? It seems straightforward but <GGGG:-)
>>
>Thanks for your help.
>>
>Bob

>
Bob - here is a simple console application that demonstrates this
method:
>
Option Explicit On
Option Strict On
>
Imports System
Imports System.Diagnost ics
>
Module Module1
>
Public Sub Main()
Dim p As Process = Process.Start(" notepad.exe")
p.WaitForExit()
Console.WriteLi ne("Done")
End Sub
>
End Module
>
>
This is a blocking operation... Another way to do this, whithout
blocking would be:
>
Option Explicit On
Option Strict On
>
Imports System
Imports System.Threadin g
Imports System.Diagnost ics
>
Module Module1
Private WithEvents p As New Process
Private exited As Boolean = False
>
Public Sub Main()
p.EnableRaising Events = True
p.StartInfo.Fil eName = "notepad.ex e"
p.Start()
>
While Not exited
Thread.Sleep(10 00)
Console.WriteLi ne("Running!")
End While
>
Console.WriteLi ne("Done")
End Sub
>
Private Sub NotepadExited(B yVal sender As Object, ByVal e As
EventArgs) Handles p.Exited
exited = True
End Sub
>
End Module
>
Anwyay - HTH,
>
--
Tom Shelton [MVP]
>

[Tom Shelton]

Re: Waiting for process end , how?

Bob wrote:

Thanks Tom,
Excellent info for me.
I've been testing the first snippet of code using Word instead of Notepad
Dim pr As Process = Process.Start(" Mydoc.doc") 'Starts Word and opens the
file OK
pr.WaitForExit( )
Console.WriteLi ne("Done")
However when execution hits the line p.WaitForExit() I get an unhandled
exception Object not set to an instance of an object. Normally this means
that I did not instantiate the pr object and indeed the code does not do
that (it would need the New keyword in he declaration) however with this
shared class you can not use the new keyword in the declaration.
>
How could I end up gettng Word to open up and have to wait before going back
to my application form that the process is closed. I look at the docs and I
see that Waitforexit does interrupt the calling thread and this is indeed
whats needed. I just don't see how to code it.
>
Any help is really, really appreciated.
>
Bob

Bob - the example I wrote works fine for me... With word as well. I
just tested it here with word to be certain.

The call to process.start returns an instance of the process class, so
there is no shared methods involved. You do not call this on the
Process class, but on the instance returned by the Process.Start
method.

I think what we need is the shortest snippet of ACTUAL code that
demonstrates the issue, since I can not replicate this problem.

--
Tom Shelton [MVP]