Parse String in Quotes as without Quotes

[vighnesh]

Hello EveryOne

In my project I have to parse a string in Quotes as without Quotes.I tried
the following code but it didn't work to me.
I again getting the string with Quotes, Can Anybody suggest me where I went
wrong?

Thanks in advance.

code:
strAssociation = "rundll32.e xe"

If strAssociation. StartsWith("""" ) Then

strAssociation = Trim(Mid(strAss ociation, 2))

If strAssociation. IndexOf("""") > 0 Then

strAssociation = Left(strAssocia tion,
strAssociation. IndexOf("""") - 1)

End If

End If

[Cor Ligthert [MVP]]

Re: Parse String in Quotes as without Quotes

Vignesh are you sure that the quotes are there, in the debugger the string
is showed with Quotes.

You have to look in a messagebox or something to see if there are no quotes.

I think that the people in the C# newsgroup are not so happy with your
crossposting by the way, with complete typical VB code.

Cor

"vighnesh" <vighnesh@nanna computers.com> schreef in bericht
news:efxVoNpeGH A.1208@TK2MSFTN GP02.phx.gbl...[color=blue]
> Hello EveryOne
>
> In my project I have to parse a string in Quotes as without Quotes.I tried
> the following code but it didn't work to me.
> I again getting the string with Quotes, Can Anybody suggest me where I
> went wrong?
>
> Thanks in advance.
>
> code:
> strAssociation = "rundll32.e xe"
>
> If strAssociation. StartsWith("""" ) Then
>
> strAssociation = Trim(Mid(strAss ociation, 2))
>
> If strAssociation. IndexOf("""") > 0 Then
>
> strAssociation = Left(strAssocia tion,
> strAssociation. IndexOf("""") - 1)
>
> End If
>
> End If
>
>[/color]

[tomb]

Re: Parse String in Quotes as without Quotes

vighnesh wrote:
[color=blue]
>Hello EveryOne
>
>In my project I have to parse a string in Quotes as without Quotes.I tried
>the following code but it didn't work to me.
>I again getting the string with Quotes, Can Anybody suggest me where I went
>wrong?
>
>Thanks in advance.
>
>code:
>strAssociati on = "rundll32.e xe"
>
>If strAssociation. StartsWith("""" ) Then
>
> strAssociation = Trim(Mid(strAss ociation, 2))
>
> If strAssociation. IndexOf("""") > 0 Then
>
> strAssociation = Left(strAssocia tion,
>strAssociation .IndexOf("""") - 1)
>
> End If
>
>End If
>
>
>
>[/color]
A string constant has to be given in quotes. A string variable will
always display its value in debug with the quotes. What is it you are
actually trying to do with this non-quoted string?

T

[John B]

Re: Parse String in Quotes as without Quotes

vighnesh wrote:[color=blue]
> Hello EveryOne
>
> In my project I have to parse a string in Quotes as without Quotes.I tried
> the following code but it didn't work to me.
> I again getting the string with Quotes, Can Anybody suggest me where I went
> wrong?
>[/color]

strAssociate = strAssociate.Tr im(new char[]{'"'});

Or you could replace the quotes with "" if you wanted to for the whole
string.

Or the quote character might just be the debugger display :)

<...>

JB

[vighnesh]

Re: Parse String in Quotes as without Quotes

ThankYou VeryMuch

Regards
Vighneswar
"John B" <jbngspam@yahoo .com> wrote in message
news:446d1d83_1 @news.iprimus.c om.au...[color=blue]
> vighnesh wrote:[color=green]
>> Hello EveryOne
>>
>> In my project I have to parse a string in Quotes as without Quotes.I
>> tried the following code but it didn't work to me.
>> I again getting the string with Quotes, Can Anybody suggest me where I
>> went wrong?
>>[/color]
>
> strAssociate = strAssociate.Tr im(new char[]{'"'});
>
> Or you could replace the quotes with "" if you wanted to for the whole
> string.
>
> Or the quote character might just be the debugger display :)
>
> <...>
>
> JB[/color]